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2 years ago

I'll mark as Brainliest, Please answer ASAP, Ihave MCAS tomorrow. How could this be true?? Please Explain.

Mathematics

1 answer:

iragen [17]2 years ago

8 0

Answer:

Step-by-step explanation:

Put m+2 in place of 'x'

(m+2)^2 + 1 <======expand

m^2 + 4m + 4 + 1 =

m^2 + 4m + 5

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The number of gift baskets Nikki can make varies directly with the amount of time she spends making the baskets . She can make 1

scoundrel [369]

Answer:

Step-by-step explanation:

The number of gift baskets Nikki can make varies directly with the amount of time she spends making the baskets .

Let n be the number of baskets and let t be the mount of time it takes to make the basket. This means that:

n α t

=> n = kt

where k = constant of proportionality

She can make 4 baskets in every 1/2 hour.

This means that:

4 = k * 1/2

=> k = 4 * 2 = 8 baskets per hour

The time is now 5 hours (t = 5). Therefore:

n = 8 * 5 = 40 baskets

She can make 40 baskets in 5 hours.

8 0

3 years ago

Compare 643,251; 633,512; and 633,893

-Dominant- [34]

The answer is 643,251 ≤633,512 ≤633,893 that's the right answer because i had it for homework before and i got it right don't forget to make it your best answer

3 0

3 years ago

Read 2 more answers

Which decimal is between √ 85 and √ 86 a)9.15 b)9.2 c)9.25 d)9.3

mina [271]

Answer:

Step-by-step explanation:

7 0

3 years ago

A hospital uses cobalt-60 in its radiotherapy treatments for cancer patients. Cobalt-60 has a half-life of 7

NeTakaya

Answer:

We have 197 g of Co-60 after 18 months.

Step-by-step explanation:

We can use the decay equation.

$M_{f}=M_{i}e^{-\lambda t}$

Where:

M(f) and M(i) are the final and initial mass respectively
λ is the decay constant (ln(2)/t(1/2))
t(1/2) is the half-life of Co
t is the time at the final amount of m

$M_{f}=228e^{-\frac{ln(2)}{7} 1.5}$

$M_{f}=197\: g$

Therefore, we have 197 g of Co-60 after 18 months.

I hope it helps you!

4 0

3 years ago

A ship leaves port at noon and has a bearing of S29oW. The ship sails at 20 knots. How many nautical miles south and how many na

ira [324]

Answer:

Approximately $58.2\; \text{nautical miles}$ (assuming that the bearing is ${\rm S$29^{\circ}$W}$ .)

Step-by-step explanation:

Let $v$ denote the speed of the ship, and let $t$ denote the duration of the trip. The magnitude of the displacement of this ship would be $v\, t$ .

Refer to the diagram attached. The direction ${\rm S$29^{\circ}$W}$ means $29^{\circ}$ west of south. Thus, start with the south direction and turn towards west (clockwise) by $29^{\circ}$ to find the direction of the displacement of the ship.

The hypothenuse of the right triangle in this diagram represents the displacement of the ship, with a length of $v\, t$ . The dashed horizontal line segment represents the distance that the ship has travelled to the west (which this question is asking for.) The angle opposite to that line segment is exactly $29^{\circ}$ .

Since the hypotenuse is of length $v\, t$ , the dashed line segment opposite to the $\theta = 29^{\circ}$ vertex would have a length of:

$\begin{aligned}& \text{opposite (to $\theta$)} \\ =\; & \text{hypotenuse} \times \frac{\text{opposite (to $\theta$)}}{\text{hypotenuse}} \\ =\; & \text{hypotenuse} \times \sin (\theta) \\ =\; & v\, t \, \sin(\theta) \\ =\; & v\, t\, \sin(29^{\circ})\end{aligned}$ .

Substitute in $\begin{aligned} v &= 20\; \frac{\text{nautical mile}}{\text{hour}}\end{aligned}$ and $t = 6\; \text{hour}$ :

$\begin{aligned} & v\, t\, \sin(29^{\circ}) \\ =\; & 20\; \frac{\text{nautical mile}}{\text{hour}} \times 6\; \text{hour} \times \sin(29^{\circ}) \\ \approx\; & 58.2\; \text{nautical mile}\end{aligned}$ .

7 0

2 years ago

I'll mark as Brainliest, Please answer ASAP, Ihave MCAS tomorrow. How could this be true?? Please Explain.​

I'll mark as Brainliest, Please answer ASAP, Ihave MCAS tomorrow. How could this be true?? Please Explain.