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2 years ago

I'll mark as Brainliest, Please answer ASAP, Ihave MCAS tomorrow. How could this be true?? Please Explain.

Mathematics

1 answer:

iragen [17]2 years ago

8 0

Answer:

Step-by-step explanation:

Put m+2 in place of 'x'

(m+2)^2 + 1 <======expand

m^2 + 4m + 4 + 1 =

m^2 + 4m + 5

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What number times itself equals 196?

leonid [27]

<span>number times itself equals 196
</span>
$= n * n = 196$

$14 * 14 = 196$

8 0

3 years ago

Read 2 more answers

(60 points)

natka813 [3]

Answer:

Step-by-step explanation:

$2.\\(a-b)^2=a^2-2ab+b^2\\\\x^2-16x=-8\\\\x^2-2(x)(8)=-8\\\\\text{We have}\ 2ab=2(x)(8).\ \text{Therefore}\ b=8.\\\\x^2-2(x)(8)=-8\qquad\text{add}\ 8^2=64\ \text{to both sides}\\\\x^2-2(x)(8)+8^2=-8+64\\\\(x-8)^2=56$

$5.\\2x^2+x-1=2\qquad\text{subtract 2 from both sides}\\\\2x^2+x-3=0\\\\2x^2+3x-2x-3=0\\\\x(2x+3)-1(2x+3)=0\\\\(2x+3)(x-1)=0\iff 2x+3=0\ \vee\ x-1=0\\\\2x+3=0\qquad\text{subtract 3 from both sides}\\2x=-3\qquad\text{divide both sides by 2}\\\boxed{x=-\dfrac{3}{2}}\\\\x-1=0\qquad\text{add 1 to both sides}\\\boxed{x=1}$

$6.\\2x^2-4x=0\qquad\text{divide both sides by 2}\\\\x^2-2x=0\\\\x(x-2)=0\iff x=0\ \vee\ x-2=0\\\\\boxed{x=0}\\\\x-2=0\qquad\text{add 2 to both sides}\\\boxed{x=2}$

8 0

3 years ago

Is w^2-9w+81 a trinomial square

Yuri [45]

No because it would be
if you knew that
ax^2+bx+c was a trinomial square, then the factored form would be
$( \sqrt{a}x+ \sqrt{c})^{2}$ or $( \sqrt{a}x- \sqrt{c})^{2}$
so
if w^2-9w+81 is perfect square, factored form is either
$( \sqrt{1}x+ \sqrt{81})^{2}$ or $( \sqrt{1}x- \sqrt{81})^{2}$ aka $( x+9)^{2}$ or $( x-9)^{2}$
expand them
(x+9)^2=x^2+18x+81, wron middle term

(x-9)^2=x^2-18x+81 wrong

so it is not

8 0

3 years ago

Identify the constant term in this expression. 25x + 9y + 20 + 2y

kvv77 [185]

20

Constant in a mathematical expression is a term whose value never changes.
The terms with x and y will vary based on the variable x and or y.

7 0

3 years ago

The gardeners at Middleton Place Gardens want to plant a total of 41 white and pink hydrangeas in one flower bed. In another flo

aev [14]

Answer:

The gardeners should buy 45 white hydrangeas and 104 pink hydrangeas.

Step-by-step explanation:

Let the gardeners at Middleton Place Gardens have to buy x numbers of white hydrangeas and y number of pink hydrangeas.

So, x + y = 41 {Given} ........... (1)

Again, for another flower bed they want to plant 108 hydrangeas, where the number of white ones is 2 times that of Middleton Place Gardens and the number of pink ones is 3 times that of Middleton Place Gardens.

So, 2x + 3y = 108 ........ (2)

Now, solving equations (1) and (2) we get,

3y - 2y = 108 - 82 = 26

⇒ y = 26

And from equation (1) we get,

x = 41 - 26 = 15.

So, the total number of white hydrangeas the gardeners have to buy is (x + 2x) = 3x = 3 × 15 = 45.

And the total number of pink hydrangeas the gardeners have to buy is (y + 3y) = 4y = 4 × 26 = 104. (Answer)

7 0

4 years ago

I'll mark as Brainliest, Please answer ASAP, Ihave MCAS tomorrow. How could this be true?? Please Explain.​

I'll mark as Brainliest, Please answer ASAP, Ihave MCAS tomorrow. How could this be true?? Please Explain.