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3 years ago

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The number of gift baskets Nikki can make varies directly with the amount of time she spends making the baskets . She can make 1

/2 hour . How many baskets can Nikki make in 5 hours

1 answer:

scoundrel [369]3 years ago

8 0

Answer:

40

Step-by-step explanation:

The number of gift baskets Nikki can make varies directly with the amount of time she spends making the baskets .

Let n be the number of baskets and let t be the mount of time it takes to make the basket. This means that:

n α t

=> n = kt

where k = constant of proportionality

She can make 4 baskets in every 1/2 hour.

This means that:

4 = k * 1/2

=> k = 4 * 2 = 8 baskets per hour

The time is now 5 hours (t = 5). Therefore:

n = 8 * 5 = 40 baskets

She can make 40 baskets in 5 hours.

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The Golden Years Senior Citizen Center uses a phone tree to announce when the center will be closed for poor weather. When each

stira [4]

Answer:

50 Minutes.

Step-by-step explanation:

The function c approximates the total number of calls made after m minutes since the start of the phone tree.

$c(m)=\frac{2}{3}\times (3^{\frac{m}{10}}-1)$

We need to find the number of minutes after which the total number of calls will 363.

Substitute c(m)=363 in the given function.

$363=\frac{2}{3}\times (3^{\frac{m}{10}}-1)$

Multiply 3/2 both sides.

$363\times \frac{3}{2}=(3^{\frac{m}{10}}-1)$

$242=3^{\frac{m}{10}}-1$

Add 1 on both sides.

$243=3^{\frac{m}{10}}$

$3^5=3^{\frac{m}{10}}$

On comparing both sides we get

$5=\frac{m}{10}$

Multiply both sides by 10.

$50=m$

Therefore, the total number of calls will 363 after 50 minutes since the start of the phone tree.

7 0

3 years ago

Read 2 more answers

Assume the random variable x is normally distributed with mean u = 90 and standard deviation o=5. Find the indicated probability

Setler79 [48]

<u>Given</u>:

Let the random variable x is normally distributed with mean $\mu=90$ and $\sigma=5$

We need to determine the probability of $P(X$

<u>Probability of </u> $P(X$ <u>:</u>

The formula to determine the value of $P(X$ is given by

$Z=\frac{X-\mu}{\sigma}$

Thus, we have;

$P(X$

Simplifying, we get;

$P(X$

$P(X$

Using the normal distribution table, the value of -2 is given by 0.0228

$P(X$

Thus, the value of $P(X$ is 0.0228

6 0

3 years ago

The radius of a circle is 9.7 m. Find the circumference to the nearest tenth?(help its urgent)

yulyashka [42]

Answer:

Step-by-step explanation:

Circumference C=2πr r=radius $\pi =3.14$

C=2(3.14)9.7

C=60.9

7 0

3 years ago

A bag contains tickets numbered 1 through 5. Use the probability distribution to determine the probability of drawing an odd num

Makovka662 [10]

Answer:

The probability of drawing an odd numbered ticket is 60%.

Step-by-step explanation:

Odd numbered tickets:

Probability of one is 1/5 plus half of 1/5.

$P(X = 1) = \frac{1}{5} + \frac{1}{10} = \frac{3}{10}$

Probability of 3 is half of 1/5.

$P(X = 3) = \frac{1}{10}$

Probability of 5 is 1/5. So

$P(X = 5) = \frac{1}{5}$

Probability of drawing an odd numbered ticket:

$p = P(X = 1) + P(X = 3) + P(X = 5) = \frac{3}{10} + \frac{1}{10} + \frac{1}{5} = \frac{4}{10} + \frac{2}{10} = \frac{6}{10} = 0.6$

0.6*100% = 60%

The probability of drawing an odd numbered ticket is 60%.

3 0

3 years ago

Write in slope intercept form, then convert to standard form Slope=1, y-intercept=-3

Viktor [21]

Slope = 1

y-intercept = -3, which can be expressed as (0,-3).

y - y_1 = m(x - x_1)

y -(-3) = 1(x - 0)

y + 3 = x

The slope-intercept form is

y = x - 3.

The standard form is Ax + By = C.

y = x - 3

3 = x - y

Done.

6 0

3 years ago