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Oksana_A [137]
2 years ago
5

The quotient of two numbers is 3 and their sum is 8 what are he two numbers

Mathematics
1 answer:
Nezavi [6.7K]2 years ago
4 0
<h2>Translating Word Equations into Numerical Equations</h2>

To change words into equations, we can recognize keywords that translate into operations and/or numbers:

  • <em>quotient</em> = divide
  • <em>a number/the number/two numbers</em> = variables
  • <em>sum</em> = add

<h2>Solving the Question</h2>

Let the two numbers be <em>a</em> and <em>b</em>.

We're given:

  • quotient of <em>a</em> and <em>b</em> is 3
    ⇒ \dfrac{a}{b}=3
  • sum of <em>a</em> and <em>b</em> is 8
    ⇒ a+b=8

First, isolate <em>a</em> in the first equation and substitute it in the second equation to solve for <em>b</em>:

\dfrac{a}{b}=3\\\\a=3b

a+b=8\\3b+b=8\\4b=8\\b=2

Therefore, one of the numbers is 2. Substitute this into one of our equations to solve for <em>a</em>:

a+b=8\\a+2=8\\a=6

Therefore, the other number is 6.

<h2>Answer</h2>

The two numbers are 2 and 6.

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A dairy farmer wants to mix a 85% protein supplement and a standard 55% protein ration to make 1200 pounds of a high-grade 80% p
mr_godi [17]

The diary farmer should use 1000 pounds of 85 % protien and 55 % of 200 pounds to make 1200 pounds of a high-grade 80% protein ration

<em><u>Solution:</u></em>

Let the amount of 85 % protien supplement be "x"

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According to given question,

85 % of "x" protien supplement + 55 % of 1200 - x protien used to get 80 % of 1200 pounds

85 % of x + 55 % of (1200 - x) = 80 % of 1200

\frac{85}{100} \times x + \frac{55}{100} \times (1200 - x) = \frac{80}{100} \times 1200\\\\0.85x + 0.55(1200 - x) = 960\\\\0.85x + 660 - 0.55x = 960\\\\0.3x = 960 - 660\\\\0.3x = 300\\\\x = 1000

Pounds of 85 % protien used = 1000 pounds

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Elimination 3x3 help please
GarryVolchara [31]
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3x + 4y + 2z =  0 ⇒ 3x + 4y + 2z =  0 ⇒  3x + 4y + 2z =   0
1x + 3y + 2z =  1                                                        x = -10

2x + 2y + 1z = -5
3x + 4y + 2z =  0 ⇒ 3x + 4y + 2z = 0
1x + 3y + 2z =  1 ⇒ 1x + 3y + 2z = 1
                                          2x + y = -1

      2x + y = -1
2(-10) + y = -1
    -20 + y = -1
  + 20       + 20
             y = 19

           2x + 2y + z = -5
2(-10) + 2(19) + z = -5
         -20 + 38 + z = -5
                  18 + z = -5
                - 18       - 18
                          z = -23
                (x, y, z) = (-10, 19, -23)
6 0
3 years ago
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