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3 years ago

How many times greater is 100 billion to 1 million.?

Mathematics

1 answer:

zalisa [80]3 years ago

8 0

Answer:

100 times

Step-by-step explanation:

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Round off 174 to the nearest hundred

shepuryov [24]

Answer: 200

Step-by-step explanation:

174 rounded to the nearest hundred is:

200

When rounding to the nearest hundred, like we did with 174 above, we use the following rules:

A) We round the number up to the nearest hundred if the last two digits in the number are 50 or above.

B) We round the number down to the nearest hundred if the last two digits in the number are 49 or below.

C) If the last two digits are 00, then we do not have to do any rounding, because it is already to the hundred.

pls mark brainliest!

4 0

2 years ago

Read 2 more answers

Which function does not have a vertical asymptote

Gemiola [76]

Answer:

$y=\frac{5x}{1+2x^2}$

Step-by-step explanation:

$Option ~A ~ does ~ not ~ have ~a ~ vertical~ asymptote$

Hope it helps...

Have a great day!!

8 0

2 years ago

Rita is hiking along a trail that is 13.8 miles long. So far she has hiked along one-tenth of the trail.

vichka [17]

Rita has hiked 1.38 miles so far.

Step-by-step explanation:

Given,

Total length of the hiking trail = 13.8 miles

Distance covered by Rita so far = $\frac{1}{10}\ of\ the\ trail$

Distance covered in miles = $\frac{1}{10}*13.8$

Distance covered in miles = 1.38 miles

Rita has hiked 1.38 miles so far.

Keywords: fraction, division

Learn more about fractions at:

#LearnwithBrainly

4 0

2 years ago

Find the laplace transform of f(t) = cosh kt = (e kt + e −kt)/2

iren2701 [21]

Hello there, hope I can help!

I assume you mean $L\left\{\frac{ekt+e-kt}{2}\right\}$
With that, let's begin

$\frac{ekt+e-kt}{2}=\frac{ekt}{2}+\frac{e}{2}-\frac{kt}{2} \ \textgreater \ L\left\{\frac{ekt}{2}-\frac{kt}{2}+\frac{e}{2}\right\}$

$\mathrm{Use\:the\:linearity\:property\:of\:Laplace\:Transform}$
$\mathrm{For\:functions\:}f\left(t\right),\:g\left(t\right)\mathrm{\:and\:constants\:}a,\:b$
$L\left\{a\cdot f\left(t\right)+b\cdot g\left(t\right)\right\}=a\cdot L\left\{f\left(t\right)\right\}+b\cdot L\left\{g\left(t\right)\right\}$
$\frac{ek}{2}L\left\{t\right\}+L\left\{\frac{e}{2}\right\}-\frac{k}{2}L\left\{t\right\}$

$L\left\{t\right\} \ \textgreater \ \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{t\right\}=\frac{1}{s^2} \ \textgreater \ L\left\{t\right\}=\frac{1}{s^2}$

$L\left\{\frac{e}{2}\right\} \ \textgreater \ \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{a\right\}=\frac{a}{s} \ \textgreater \ L\left\{\frac{e}{2}\right\}=\frac{\frac{e}{2}}{s} \ \textgreater \ \frac{e}{2s}$

$\frac{ek}{2}\cdot \frac{1}{s^2}+\frac{e}{2s}-\frac{k}{2}\cdot \frac{1}{s^2}$

$\frac{ek}{2}\cdot \frac{1}{s^2} \ \textgreater \ \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \ \frac{ek\cdot \:1}{2s^2} \ \textgreater \ \mathrm{Apply\:rule}\:1\cdot \:a=a$
$\frac{ek}{2s^2}$

$\frac{k}{2}\cdot \frac{1}{s^2} \ \textgreater \ \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \ \frac{k\cdot \:1}{2s^2} \ \textgreater \ \mathrm{Apply\:rule}\:1\cdot \:a=a$
$\frac{k}{2s^2}$

$\frac{ek}{2s^2}+\frac{e}{2s}-\frac{k}{2s^2}$

Hope this helps!

3 0

3 years ago

Please help me out with this :)

Misha Larkins [42]

Answer:

x = 1

Step-by-step explanation:

Given that y varies directly with x then the equation relating them is

y = kx ← k is the constant of variation

To find k use the condition y = 12 when x = - 2, then

k = $\frac{y}{x}$ = $\frac{12}{-2}$ = - 6, thus

y = - 6x ← equation of variation

When y = - 6, then

- 6 = - 6x ( divide both sides by - 6 )

x = 1

8 0

3 years ago