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Advocard [28]
2 years ago
7

I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS AND EXPLAIN WHY THAT IS THE ANSWER. Find the area of t

he figure.
___m^2 (Simplify your answer)

Mathematics
2 answers:
dem82 [27]2 years ago
8 0

Answer:

easy 230-80 which is 150 so imagine a triangle with base 150 and hight 130-60=70 so times for area 150×70÷2 because it's triangle which is <em>5</em><em>2</em><em>5</em><em>0</em> so plus that with 130x80 for rectangle which is 10400 and add so it's 15650

valkas [14]2 years ago
5 0

Answer:

15650{m}^{2}

Step-by-step explanation:

To find the area you first split the shape in two; a triangle and a rectangle.

Since the opposite sides of a rectangle are always equal we can assume that the right side of the rectangle is also 130m and the top is also 80m. This would mean that 80 meters from the 230 meters that is given as the measurement for the top of the entire shape would be for the rectangle. This also means that the remaining 150 meters would be the measurement for the height of the triangle.

Also assuming that the right side of the rectangle is 130 meters we can then subtract the 60 meters that was given in the question *from* the 130 meters to find the measurement for the base of the triangle, which would be 70 meters.

Now we add the area of the rectangle and the triangle to find the area of the entire shape.

area of triangle: 1/2 base x height

1/2(70) x 150 = 5250

area of rectangle: length x width

130 x 80 = 10,400

area of triangle + area of rectangle

<em>52</em><em>5</em><em>0</em><em>+</em><em>1</em><em>0</em><em>4</em><em>0</em><em>0</em><em> </em><em>=</em><em> </em><em>1565</em><em>0</em>

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is 58in. an answer?

Step-by-step explanation:

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6 0
2 years ago
Read 2 more answers
The length of a rectangle is 5 m greater than the width. The perimeter is 150 m. find the width
Elza [17]

P = perimeter

Perimeter of a rectangle = l + l + w + w

or  P = 2l + 2w

You know:

P = 150 m

l = w + 5     [length is 5 m greater than the width]

P = 2l + 2w        Plug in what you know

150 = 2(w + 5) + 2w     Simplify, distribute/multiply 2 into (w + 5)

150 = 2w + 10 + 2w

150 = 4w + 10     Subtract 10 to both sides of the equation

140 = 4w       Divide 4 on both sides

35 = w

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P = 2l + 2w

150 = 2(40) + 2(35)

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For a limit to exist, it must be the same regardless of the direction of approach.

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