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qaws [65]
3 years ago
14

What is the factored form of the expression. (2n^2 + 5n + 3) (4n - 5)

Mathematics
1 answer:
7nadin3 [17]3 years ago
7 0

So firstly, <u>the factor (4n - 5) cannot be further factored, so we will be focusing on 2n² + 5n + 3.</u>

So for this, we will be factoring by grouping. Firstly, what two terms have a product of 6n² and a sum of 5n? That would be 2n and 3n. Replace 5n with 2n + 3n:

(2n^2 + 2n + 3n + 3)(4n - 5)

Next, factor 2n² + 2n and 3n + 3 separately. Make sure that they have the same quantity on the inside of the parentheses:

(2n(n+1)+3(n+1))(4n-5)

Now we can rewrite this expression as<u> (2n+3)(n+1)(4n-5) , which is your final answer.</u>

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Jane buys some rocks for decorating her backyard. She uses a box full of rocks. The box is a rectangular container that is 1 yar
statuscvo [17]
First, Jane must know the volume of the box.
Volume = l * w * h
Volume = 1 * 0.5 * 0.5
Volume = 0.25 yard^3

1 yard^3 = $25

So,
1 : 25 = 0.25 : x
x = 25 * 0.25
x = $6.25

So she need to spend $6.25
4 0
3 years ago
PLZ SOMEONE HELP ME AND EXPLAIN <br> THX
ELEN [110]
The graph of g is one-fifth as steep as the graph of f.

The function g basically takes the inputs for f and multiplies them by one-fifth, which means the outputs are one-fifth times those of f. Multiplying by one-fifth makes something smaller (it's the same as dividing by five). It helps to visualize this relationship, so I've attache the graphs below.

7 0
3 years ago
Im dum on this but smart on other things look at points too...
Over [174]

Step-by-step explanation:

Whole numbers = Natural numbers + "0"

Integers = Whole numbers + Negative counterparts

Since the set do contains negative numbers, only Rational numbers and Integers are correct. (D)

4 0
3 years ago
Suppose that the population mean for income is $50,000, while the population standard deviation is 25,000. If we select a random
Fudgin [204]

Answer:

Probability that the sample will have a mean that is greater than $52,000 is 0.0057.

Step-by-step explanation:

We are given that the population mean for income is $50,000, while the population standard deviation is 25,000.

We select a random sample of 1,000 people.

<em>Let </em>\bar X<em> = sample mean</em>

The z-score probability distribution for sample mean is given by;

               Z = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \mu = population mean = $50,000

            \sigma = population standard deviation = $25,000

            n = sample of people = 1,000

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, probability that the sample will have a mean that is greater than $52,000 is given by = P(\bar X > $52,000)

  P(\bar X > $52,000) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{52,000-50,000}{\frac{25,000}{\sqrt{1,000} } } ) = P(Z > 2.53) = 1 - P(Z \leq 2.53)

                                                                    = 1 - 0.9943 = 0.0057

<em>Now, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2.53 in the z table which has an area of 0.9943.</em>

Therefore, probability that the sample will have a mean that is greater than $52,000 is 0.0057.

5 0
3 years ago
CINDY made costume decorations. She used 1/10 of a meter of ribbon for each decoration which she got by cutting 3/10 of a meter
Brilliant_brown [7]

Answer:

Cindy made 3 decorations with the ribbons

Step-by-step explanation:

Since Cindy used 1/10 of a metre of ribbon to make just one decoration that she obtained by dividing 3/10 of a meter of ribbon into equal parts, then we can calculate the number of decorations that Cindy made. In this scenario, all we need is an idea on how to divide fractions and we are good to go.

If Cindy used 1/10 of a metre obtained by dividing 3/10 of a metre of ribbon to make decorations, then the number of decorations she made can be gotten by dividing 3/10 by 1/10

i.e 3/10 ÷ 1/10

= 3/10 × 10/1

= 3 decorations.

That is she used 1/10 + 1/10 + 1/10 = 3/10 to make (3 decorations).

3 0
3 years ago
Read 2 more answers
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