You pick a card at random.

Mathematics

2 answers:

AfilCa [17]2 years ago

6 0

Answer:

$40\%$

Step-by-step explanation:

$P(X > 4)=P(5)+P(6)=\frac{1}{5}+\frac{1}{5}=\frac{2}{5}=40\%$

GenaCL600 [577]2 years ago

4 0

Answer:

P(greater than 4) = $40\%$

Step-by-step explanation:

There are 5 given numbers (2 , 3 , 4 , 5 , 6). You are solving for the probability of obtaining a card greater than (and not equal to 4). In this case, there will be two numbers (5 & 6). Find the probability:

P(greater than 4) = (Amount of numbers greater than 4/Total amount of numbers) = $\frac{2}{5}$ .

Next, find the percentage:

$\frac{2}{5} * \frac{20}{20} = \frac{40}{100} = 0.40 = 40\%$

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klemol [59]

Answer:

The differential equation which describes the mixing process is $\frac{dc_{salt,out}}{dt} + \frac{2}{125}\cdot c_{salt,out} = \frac{71}{100000}$ .

Step-by-step explanation:

The mixing process within the tank is modelled after the Principle of Mass Conservation, which states that:

$\dot m_{salt,in} - \dot m_{salt,out} = \frac{dm_{tank}}{dt}$

Physically speaking, mass flow of salt is equal to the product of volume flow of water and salt concentration. Then:

$\dot V_{water, in, 1}\cdot c_{salt, in,1} + \dot V_{water, in, 2} \cdot c_{salt,in, 2} - \dot V_{water, out}\cdot c_{salt, out} = V_{tank}\cdot \frac{dc_{salt,out}}{dt}$

Given that $\dot V_{water, in, 1} = 9\,\frac{L}{min}$ , $\dot V_{water, in, 2} = 7\,\frac{L}{min}$ , $c_{salt,in,1} = 0.04\,\frac{kg}{L}$ , $c_{salt, in, 2} = 0.05\,\frac{kg}{L}$ , $\dot V_{water, out} = 16\,\frac{L}{min}$ and $V_{tank} = 1000\,L$ , the differential equation that describes the system is: