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yan [13]
3 years ago
10

Please help thanks a(n)=−6+3(n−1)

Mathematics
1 answer:
erica [24]3 years ago
5 0

Answer:

a=-1

Step-by-step explanation:

a(n) = -6+3(n-1)

a(n) = -6+3n-3

a(n) -n=-6+3n-n-3

a=-6+3-3

+3 +3

a3=-3

---- ----

3 3

a=-1

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Determine how far the vehicle travels in 3 hours.
Karo-lina-s [1.5K]

Answer:

360 miles

Step-by-step explanation:

The unit rate here is (240 miles) / (2 hours), or 120 mph.

In 3 hours the vehicle travels (120 mph)(3 hrs) = 360 miles

8 0
2 years ago
(2+5xyz-6tv²c)-(11-5yxz-2ctv²)​
Effectus [21]

Answer:

-4ctv² + 10xyz - 9

Step-by-step explanation:

(2 + 5xyz - 6tv²c) - (11 - 5yxz - 2ctv²)

2 + 5xyz - 6tv²c - 11 + 5yxz + 2ctv²

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I hope this helps!

5 0
1 year ago
Recognize whether the fractions are Cleveland right yes Arnel use fraction tiles or number lines
wolverine [178]
1. No sorry I just know #1
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2 years ago
Devon records 4 hours of reality shows on her DVR she records comedy shows for 3/8 of that amount of time. Devon watches all the
Alenkinab [10]

The number of half-hour sittings needed to watch all the shows by Devon is 11

<u>Solution:</u>

Given, Devon records 4 hours of reality shows on her DVR  

she records comedy shows for 3/8 of that amount of time.  

\rightarrow \frac{3}{8} \text { of } 4 \text { hours } \rightarrow \frac{3}{8} \times 4 \rightarrow \frac{3}{2} \text { hours }

Devon watches all the reality and comedy shows in half-hour sittings.

We have to find the number of half-hour sittings needed to watch all the shows

Now, number of half hour sittings is given as

=\frac{\text { total time of videos }}{\text { time for hlaf hour sitting }}

\begin{array}{l}{=\frac{4 \text { hours for reality shows }+\frac{3}{2} \text { hours for comedy shows }}{\frac{1}{2} \text { hours for each sitting }}} \\\\ {=\frac{4+\frac{3}{2}}{\frac{1}{2}}=\frac{\frac{8+3}{2}}{\frac{1}{2}}=\frac{\frac{11}{2}}{\frac{1}{2}}=\frac{11}{2} \times \frac{2}{1}=11}\end{array}

Hence Devon needs 11 sittings

3 0
3 years ago
The elevation of lake sam rayburn is 164 above mean sea level during the summer if it does not rain the elevation of the lake de
andrew-mc [135]

Answer:

I guess that you want to model the elevation of Lake Sam Rayburn.

During the summer, it is 165 ft above the sea level (the sea level is our position 0ft).

If it does not rain, the elevation of the lake decreases by 0.5ft each week.

So if we assume that there is no rain, we can write the elevation fo the lake as a linear relationship with slope equal to -0.5ft and y-intercept equal to 165ft.

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4 0
3 years ago
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