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maks197457 [2]
2 years ago
5

100 point please help​

Mathematics
2 answers:
nekit [7.7K]2 years ago
6 0

Answer:

Step-by-step explanation:

16 in is close to 18 in and 18 is cool

Allushta [10]2 years ago
3 0

Answer:

Step-by-step explanation:

You might be interested in
The vertices of a right triangle are (0, 0), (1, 0), and (0, 1).
Alchen [17]

Answer:

(3,3)

Step-by-step explanation:

Given

Vertices: (0,0)\ (1,0)\ (0,1)

Scale\ Factor = 3

Required

Determine which can't be any of the new vertices

First, we need to determine the new vertices:

New\ Vertex = Scale\ Factor * Old\ Vertex

For (0,0):

New\ Vertex = 3 * (0,0)

New\ Vertex = (3 * 0,3 * 0)

New\ Vertex = (0,0)

For (1,0):

New\ Vertex = 3 * (1,0)

New\ Vertex =  (3 * 1,3 * 0)

New\ Vertex =  (3,0)

For (0,1):

New\ Vertex =  3 * (0,1)

New\ Vertex =  (3 * 0,3 * 1)

New\ Vertex =  (0,3)

<em>Comparing the calculated new vertices to the list of given options; (3,3) can't be any of the new vertices of the new triangle</em>

<em></em>

5 0
4 years ago
Simplify <br> 3x+4.4-2(6.6+x)
Taya2010 [7]
Im not 100% sure but I think it’s X-8.8
7 0
2 years ago
Find the distance between points P(5, 1) and Q(1, 3) to the nearest tenth.
bonufazy [111]

Answer:

Idk if its multiple choice but you can do 1 of 2 ways theres using distance formula =√(5-3)sq+(1-4)sq

=√4+9

=√13 <--

or

3.6 units

Given: The two points that are P(5,1) and Q(3,4).

To find: The distance between these two points.

Solution: It is given that there are two points that are P(5,1) and Q(3,4).

The distance between these two points can be found out as using the distance formula that is: 3.6

Thus, the distance between the given two points is 3.6 units.

So you choose 13 or 3.6 Hope this helps :)

3 0
3 years ago
(b) Kevin ran 4 miles more than Steve ran. The sum of their distances is 26 miles. How far did Steve run? The domain of the solu
kotegsom [21]
S=Steve. S+4=Kevin. S+s+4=26. Combine: 2s+4=26. Subtract 4: 2s=22. Divide by 2: s=11. Steve ran 11 miles. :)
5 0
3 years ago
I can't figure this out
andriy [413]
Suppose that equation of parabola is
y =ax² + bx + c


Since parabola passes through the point (2,−15) then 
−15 = 4a + 2b + c

Since parabola passes through the point (-5,-29), then
−29 = 25a − 5b + c

Since parabola passes through the point (−3,−5), then 
−5 = 9a − 3b + c


Thus, we obtained following system:
4a + 2b + c = −15
25a − 5b + c = −29
9a − 3b + c = −5

Solving it we get that 
a = −2, b = −4, c = 1

Thus, equation of parabola is
y = −2x²− 4x + 1

____________________

Rewriting in the form of 
(x - h)² = 4p(y - k)

i) -2x² - 4x + 1 = y

ii) -3x² - 7x = y - 11
(-3x² and -7x are isolated)

iii) -3x² - 7x - 49/36 = y - 1 - 49/36
(Adding -49/36 to both sides to get perfect square on LHS)

iv) -3(x² + 7/3x + 49/36) = y - 3
(Taking out -3 common from LHS)

v) -3(x + 7/6)² = y - 445/36 

vi) (x + 7/6)² = -⅓(y - 445/36) 
(Shifting -⅓ to RHS)

vii) (x + 1)² = 4(-1/12)(y - 445/36)
(Rewriting in the form of 4(-1/12) ; This is 4p) 


So, after rewriting the equation would be - 

(x + 7/6)² = 4(-⅛)(y - 445/36)

__________________

I hope this is what you wanted.

Regards,
Divyanka♪
__________________
6 0
3 years ago
Read 2 more answers
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