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sattari [20]
3 years ago
9

Help asap plz, hehdbjdnejxjfbrjdjcnbd

Mathematics
2 answers:
dlinn [17]3 years ago
7 0
The answer is 140
(Sorry if I didn’t explain I was in a hurry)
Rzqust [24]3 years ago
5 0

Answer:

140

Step-by-step explanation:

Solves equation:

20x+60=30x+20

They are the same angles.

<u><em>Sorry, I was in hurry so the answer isn't detailed. I hope it still helps.</em></u>

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Please help me and thank you
kati45 [8]

Answer:

Some number less than 5

Step-by-step explanation:

If it was more we wouldn't need to subtract to find n.

6 0
3 years ago
Read 2 more answers
+3 0 -4 +1 +5 -2 from lowest to highest
weqwewe [10]

Answer:

-4, -2, 0, 1, 3   <--- lowest to highest

3 0
2 years ago
Read 2 more answers
Help me fill in the blanks pleasee
777dan777 [17]

Answers and Step-by-step explanations:

Let's look at the first row:

cost = _______ + _______ * (monthly payment)

The first blank should be the "down payment" because this is the initial, constant value that is paid. The second blank should be the "number of months" because this way, when multiplied by the actual amount each payment is (monthly payment), then we get the total amount paid during those months.

So, we have:

cost = (down payment) + (number of months) * (monthly payment)

Now for the second row, we just plug in numbers and variables:

335 = 50 + 6 * p

Finally, we can solve for p:

335  = 50 + 6p

6p = 285

p = $47.50

8 0
2 years ago
Read 2 more answers
What are the slope and y intercept of the line 4y= -x - 32
Alona [7]
First you'll have to bring the equation in form y = mx + b.

4y = -x - 32
y = -1/4 x - 8

So the slope is -1/4 and y-intercept is -8

Hope this helps :)
7 0
2 years ago
Read 2 more answers
One container is filled with mixture that is 25% acid. A second container is filled with a mixture that is 55% acid. The second
algol13

Answer:

Therefore the third container contains   \frac{735}{17}\% = 43.23 %  acid.

Step-by-step explanation:

Given that, One container is filled with the mixture that 25% acid. 55% acid is contain by second container.

Let the volume of first container be x cubic unit.

Since the volume of second container is 55% larger than the first.

Then the volume of the second container is

= (V\times \frac{100+55}{100})   cubic unit.

=\frac{155}{100}V  cubic unit.

The amount of acid in first container is

=V\times \frac{25}{100}  cubic unit.

=\frac{25}{100}V  cubic unit.

The amount of acid in second container is

=(\frac{155}{100}V \times \frac{55}{100}) cubic unit.

=\frac{8525}{10000}V cubic unit.

Total amount of acid =(\frac{25}{100}V+\frac{8525}{10000}V) cubic unit.

                                   =(\frac{2500+8525}{10000}V) cubic unit.

                                   =(\frac{11025}{10000}V)cubic unit.

Total volume of mixture =(V+\frac{155}{100}V) cubic unit.

                                       =\frac{100+155}{100}V cubic unit.

                                       =\frac{255}{100}V  cubic unit.

The amount of acid in the mixture is

=\frac{\textrm{The volume of acid}}{\textrm{The amount of mixture}}\times 100 \%

=\frac {\frac{11025}{10000}V}{\frac{255}{100}V}\times 100\%

=\frac{735}{17}\%

Therefore the third container contains  \frac{735}{17}\%  acid.

5 0
3 years ago
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