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EleoNora [17]
3 years ago
14

PLEASE HELP ME!! find the Trinomial!​

Mathematics
1 answer:
vichka [17]3 years ago
6 0

Answer:

a^{4}-2a^{2}  -24

Step-by-step explanation:

We do FOIL to solve this

Download pdf
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A rectangle has a width of 20 inches. The diagonal measure of the rectangle from
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600.0

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Help in geometry asap please!!
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Graph the image of this figure after a dilation with a scale factor of 13 centered at the point (4, −2) .
Sonja [21]

Answer:

From the given triangle figure;

Labelled the triangle as A , B and C.

The coordinates of this triangle ABC  are;

A = (1, 10) ,

B = (-2, 4)

C = (7, 4).

Given : Scale factor(k) = \frac{1}{3} and centered at point (4, -2).

The rule of dilation with k= \frac{1}{3} and center at point (4,-2) is:

(x, y) \rightarrow (\frac{1}{3}(x-4)+4 , \frac{1}{3}(y+2)-2)

(x, y) \rightarrow (\frac{1}{3}x-\frac{4}{3}+4 , \frac{1}{3}y+\frac{2}{3}-2)

or

(x, y) \rightarrow (\frac{1}{3}x+\frac{8}{3} , \frac{1}{3}y-\frac{4}{3})

then, the dilation of the given figure are;

A(1, 10) \rightarrow (\frac{1}{3}\cdot 1+\frac{8}{3} , \frac{1}{3} \cdot 10-\frac{4}{3}) = (\frac{1}{3}+\frac{8}{3} , \frac{10}{3}-\frac{4}{3}) =(\frac{9}{3} , \frac{6}{3}) = A'(3 , 2)

B(-2, 4) \rightarrow (\frac{1}{3}\cdot -2+\frac{8}{3} , \frac{1}{3} \cdot 4-\frac{4}{3}) =(-\frac{2}{3}+\frac{8}{3} , \frac{4}{3}-\frac{4}{3}) =(\frac{6}{3} , \frac{0}{3}) =B'(2 , 0)

C(7, 4) \rightarrow (\frac{1}{3}\cdot 7+\frac{8}{3} , \frac{1}{3} \cdot 4-\frac{4}{3}) =(\frac{7}{3}+\frac{8}{3} , \frac{4}{3}-\frac{4}{3}) =(\frac{15}{3} , \frac{0}{3}) = C'(5 , 0)

The coordinates of dilation images are:

A' = (3,2) , B' = (2, 0) and C' = (5, 0)

You can see the graph of the dilated image as shown below:

3 0
3 years ago
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Put these fractions in order from least to greatest. 3/12 1/6 2/3
Shtirlitz [24]

Answer:1

1/6 3/12 2/3

Step-by-step explanation:

3/12 = 2/6

2/3 = 4/6

1/6<2/6<2/3

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