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guajiro [1.7K]
3 years ago
8

1000 mL of D5W is ordered to be infused over 5 hours. The drop factor is 10 gtt/mL. How many gtt/min should be given to infuse t

he 1000 mL over 5 hours?
Mathematics
1 answer:
Levart [38]3 years ago
5 0

Answer:

flow rate of to infuse the 1000 mL over 5 hours is 33.33 gtt/min

Step-by-step explanation:

Given data

volume = 1000 mL

time =  5 hours

drop factor = 10 gtt/min

to find out

flow rate of to infuse the 1000 mL over 5 hours

Solution

we know flow rate formula  i.e.

flow rate =  ( volume × drop factor )  / time   .................1

here time will be in min so time =  5 hours = 5  × 60 = 300 min

put volume, drop factor and time value in equation 1 and we get flow rate

flow rate =  ( volume × drop factor )  / time

flow rate =  ( 1000 × 10 )  / 300

flow rate = 33.33 gtt/min

flow rate of to infuse the 1000 mL over 5 hours is 33.33 gtt/min

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2 years ago
If measure of angle 1 = 2x+6 and measure of angle 2 = 8x+4 where angles 1 and 2 are supplementary, then how much is the actual m
nlexa [21]

Answer:

The actual measure of ∠1 = 40°

Step-by-step explanation:

We are given: ∠1 = 2x+6 and ∠2 = 8x+4

and both angles are supplementary. we need to find the actual measure of ∠1

Supplementary angles: If the angles are supplementary their sum is equal to 180°

In our case ∠1 +∠2 = 180°

2x+6+8x+4=180

Solving the equation to find x, then we can find the actual measure of ∠1

2x+6+8x+4=180\\10x+10=180\\10x=180-10\\10x=170\\x=170/10\\x=17

So, value of x = 17

Now, finding actual measure of ∠1 by putting x=17 in equation 2x+6

\angle1=2(17)+6\\\angle1=34+6\\\angle1=40

So, the actual measure of ∠1 = 40°

8 0
2 years ago
What are the coordinates of the orthocenter of △JKL with vertices at J(−4, −1) , K(−4, 8) , and L(2, 8) ?
kompoz [17]

Answer:

K(-4,8) is the ortho center.

Step-by-step explanation:

In a right angled triangle, The vertex of the right angle is the ortho center.

Here we are given

J(-4,-1), K(-4,8) & L(2,8)

Using distance formula we get

JK^{2}= (-4+4)^{2}+ (8+1)^{2}=0+81=81

KL^{2}= (-4-2)^{2}+ (8+-8)^{2}=36+0=36

JL^{2}= (-4-2)^{2}+ (8+1)^{2}=36+81=117

So we can say that

JK^2 + KL^2=JL^2

By converse of pythagorean theorem we get

Hence the Vertex of the right angle is K(-4,8)

K(-4,8) is the ortho center.

7 0
3 years ago
The Precision Scientific Instrument Company manufactures thermometers that are supposed to give readings of 0degrees°C at the fr
Sergio039 [100]

Answer:

Step-by-step explanation:

Hello!

The variable of study is X: Temperature measured by a thermometer (ºC)

This variable has a distribution approximately normal with mean μ= 0ºC and standard deviation σ= 1.00ºC

To determine the value of X that separates the bottom 4% of the distribution from the top 96% you have to work using the standard normal distribution:

P(X≤x)= 0.04 ⇒ P(Z≤z)=0.04

First you have to use the Z tables to determine the value of Z that accumulates 0.04 of probability. It is the "bottom" 0.04, this means that the value will be in the left tail of the distribution and will be a negative value.

z= -1.75

Now using the formula of the distribution and the parameters of X you have to transform the Z-value into a value of X

z= (X-μ)/σ

z*σ = X-μ

(z*σ)+μ = X

X= (-1.75-0)/1= -1.75ºC

The value that separates the bottom 4% is -1.75ºC

I hope this helps!

5 0
3 years ago
Please Help ASAP!!!<br> Question in image below.
umka21 [38]

Answer:

17, they are both equal to eachother

4 0
3 years ago
Read 2 more answers
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