All categories

3 years ago

Why are triangles congruent ?

Mathematics

2 answers:

Karolina [17]3 years ago

8 0

So if you have two triangles and you can transform one of them into the other ,the two triangles are congruent

Andru [333]3 years ago

6 0

Explanation:

Basically triangles are congruent when they have the same shape and size.

Two triangles are congruent if they have :

exactly the same three sides and

exactly the same three angles.

Tips Area :

If two sides and the included angle of one triangle are equal to the corresponding sides and angle of another triangle, the triangles are congruent too :)

If two angles and the included side of one triangle are equal to the corresponding angles and side of another triangle, the triangles are congruent too ;)

If two angles and the non-included side of one triangle are equal to the corresponding angles and side of another triangle, the triangles are congruent too ^^

Hope that help :)

You might be interested in

The Department of Agriculture is monitoring the spread of mice by placing 100 mice at the start of the project. The population,

uranmaximum [27]

Answer:

Step-by-step explanation:

Assuming that the differential equation is

$\frac{dP}{dt} = 0.04P\left(1-\frac{P}{500}\right)$ .

We need to solve it and obtain an expression for $P(t)$ in order to complete the exercise.

First of all, this is an example of the logistic equation, which has the general form

$\frac{dP}{dt} = kP\left(1-\frac{P}{K}\right)$ .

In order to make the calculation easier we are going to solve the general equation, and later substitute the values of the constants, notice that $k=0.04$ and $K=500$ and the initial condition $P(0)=100$ .

Notice that this equation is separable, then

$\frac{dP}{P(1-P/K)} = kdt$ .

Now, intagrating in both sides of the equation

$\int\frac{dP}{P(1-P/K)} = \int kdt = kt +C$ .

In order to calculate the integral in the left hand side we make a partial fraction decomposition:

$\frac{1}{P(1-P/K)} = \frac{1}{P} - \frac{1}{K-P}$ .

So,

$\int\frac{dP}{P(1-P/K)} = \ln|P| - \ln|K-P| = \ln\left| \frac{P}{K-P} \right| = -\ln\left| \frac{K-P}{P} \right|$ .

We have obtained that:

$-\ln\left| \frac{K-P}{P}\right| = kt +C$

which is equivalent to

$\ln\left| \frac{K-P}{P}\right|= -kt -C$

Taking exponentials in both hands:

$\left| \frac{K-P}{P}\right| = e^{-kt -C}$

Hence,

$\frac{K-P(t)}{P(t)} = Ae^{-kt}$ .

The next step is to substitute the given values in the statement of the problem:

$\frac{500-P(t)}{P(t)} = Ae^{-0.04t}$ .

We calculate the value of $A$ using the initial condition $P(0)=100$ , substituting $t=0$ :

$\frac{500-100}{100} = A}$ and $A=4$ .

So,

$\frac{500-P(t)}{P(t)} = 4e^{-0.04t}$ .

Finally, as we want the value of $t$ such that $P(t)=200$ , we substitute this last value into the above equation. Thus,

$\frac{500-200}{200} = 4e^{-0.04t}$ .

This is equivalent to $\frac{3}{8} = e^{-0.04t}$ . Taking logarithms we get $\ln\frac{3}{8} = -0.04t$ . Then,

$t = \frac{\ln\frac{3}{8}}{-0.04} \approx 24.520731325$ .

So, the population of rats will be 200 after 25 months.

6 0

3 years ago

Help me please ^^ much appreciated

Reil [10]

Answer:

Step-by-step explanation:

Using the sine ratio in the right triangle.

sinC = $\frac{opposite}{hypotenuse}$ = $\frac{AB}{BC}$ = $\frac{16}{28}$ , thus

∠ C = $sin^{-1}$ ( $\frac{16}{28}$ ) ≈ 34.85° ( to 2 dec. places )

8 0

2 years ago

How didi the temperature change if at it decreased by 60% then increased by 80%

leonid [27]

Answer:

It decreased

Step-by-step explanation:

It decreased. Assuming that the temperature is 100 and it is now reduced by 60% then the temperature will be at 40 and if it increased by 80% then the final temp is 72. So it is 48% of the original temp.

5 0

2 years ago

If Steve throws the football 50 meters in 3 seconds, what is the average speed of the football? Speed = distance / time

ankoles [38]

Answer:

i used calculator

6 0

3 years ago

Read 2 more answers

Please Help ASAP! What is the measure of Angle WZY

ivanzaharov [21]

Answer: 138