Subtract 1/3x from the left side of the equation and subtract it from the right side of the equation. So it would be y = 4 - 1/3x
Answer:
Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate
10%. The second car depreciates at an annual rate of 15%. What is the approximate difference in the ages of the two
cars?
Step-by-step explanation:
the answer is in the question
Answer:
x = 10 or x = 2
Step-by-step explanation:
Solve for x:
x^2 - 12 x + 20 = 0
Hint: | Solve the quadratic equation by completing the square.
Subtract 20 from both sides:
x^2 - 12 x = -20
Hint: | Take one half of the coefficient of x and square it, then add it to both sides.
Add 36 to both sides:
x^2 - 12 x + 36 = 16
Hint: | Factor the left hand side.
Write the left hand side as a square:
(x - 6)^2 = 16
Hint: | Eliminate the exponent on the left hand side.
Take the square root of both sides:
x - 6 = 4 or x - 6 = -4
Hint: | Look at the first equation: Solve for x.
Add 6 to both sides:
x = 10 or x - 6 = -4
Hint: | Look at the second equation: Solve for x.
Add 6 to both sides:
Answer: x = 10 or x = 2
