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3 years ago

How to tell that faction is unit fraction

2 answers:

7 0

Multiply the denominator by the whole number. Make that product the numerator. Let us now revisit the rule for changing a mixed number to an improper fraction<span> (Lesson 20).</span>

MaRussiya [10]3 years ago

5 0

Like this 2/5 that's how you know

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Drag the expressions into the boxes to correctly complete the table.

lora16 [44]

Answer:

SUMMARY:

$x^4+\frac{5}{x^3}-\sqrt{x}+8$ → Not a Polynomial

$-x^5+7x-\frac{1}{2}x^2+9$ → A Polynomial

$x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi$ → A Polynomial

$\left|x\right|^2+4\sqrt{x}-2$ → Not a Polynomial

$x^3-4x-3$ → A Polynomial

$\frac{4}{x^2-4x+3}$ → Not a Polynomial

Step-by-step explanation:

The algebraic expressions are said to be the polynomials in one variable which consist of terms in the form $ax^n$ .

Here:

$n$ = non-negative integer

$a$ = is a real number (also the the coefficient of the term).

Lets check whether the Algebraic Expression are polynomials or not.

Given the expression

$x^4+\frac{5}{x^3}-\sqrt{x}+8$

If an algebraic expression contains a radical in it then it isn’t a polynomial. In the given algebraic expression contains $\sqrt{x}$ , so it is not a polynomial.

Also it contains the term $\frac{5}{x^3}$ which can be written as $5x^{-3}$ , meaning this algebraic expression really has a negative exponent in it which is not allowed. Therefore, the expression $x^4+\frac{5}{x^3}-\sqrt{x}+8$ is not a polynomial.

Given the expression

$-x^5+7x-\frac{1}{2}x^2+9$

This algebraic expression is a polynomial. The degree of a polynomial in one variable is considered to be the largest power in the polynomial. Therefore, the algebraic expression is a polynomial is a polynomial with degree 5.

Given the expression

$x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi$

in a polynomial with a degree 4. Notice, the coefficient of the term can be in radical. No issue!

Given the expression

$\left|x\right|^2+4\sqrt{x}-2$

is not a polynomial because algebraic expression contains a radical in it.

Given the expression

$x^3-4x-3$

a polynomial with a degree 3. As it does not violate any condition as mentioned above.

Given the expression

$\frac{4}{x^2-4x+3}$

$\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}$

Therefore, is not a polynomial because algebraic expression really has a negative exponent in it which is not allowed.

SUMMARY:

$x^4+\frac{5}{x^3}-\sqrt{x}+8$ → Not a Polynomial

$-x^5+7x-\frac{1}{2}x^2+9$ → A Polynomial

$x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi$ → A Polynomial

$\left|x\right|^2+4\sqrt{x}-2$ → Not a Polynomial

$x^3-4x-3$ → A Polynomial

$\frac{4}{x^2-4x+3}$ → Not a Polynomial

3 0

3 years ago

So can someone show there work in this one?

mihalych1998 [28]

just separate the ramge and domain

4 0

3 years ago

if rounded to the nearest dime what is the greatest amount of money that rounds to $105.40? what is the least amount of money th

Kamila [148]

The greatest amount of money would be $105.40. The least amount would also be $105.40. Because the zero is less than five the dollar amount would stay the same.

4 0

3 years ago

Read 2 more answers

Add and simplify: 9/16 + 1/2=?

kozerog [31]

9/16+ 1/2
= 9/16+ (1*8) / (2*8)
= 9/16+ 8/16 (common denominator is 16)
= (9+8)/16
= 17/16
= (16+1)/16
= 16/16+ 1/16
= 1+ 1/16
= 1 1/16

The final answer is 1 1/16~

8 0

3 years ago

Read 2 more answers

Bill drives and sees a red light. He slows down to a stop. A graph of his velocity over time is shown below. What is his average

Feliz [49]

Answer:

Step-by-step explanation:Velocity at t= 0s is 20m/s and the velocity at t= 10s is 20m/s.

a= 20-20/ 10s

a=0m/s

4 0

3 years ago