Hello its my birthday please help!!

Write the equation of the line that passes through the points (2, 1) and (5, -8)

My name is Ann [436]

Answer:

The answer is y = -3x + 7.

Step-by-step explanation:

❃Incase you forgot what the linear equation formula is ☟

$y = mx + b$

❃Incase you also forgot, what the slope formula is ☟

$m = \frac{y_2 - y_1}{x_2 - x_1}$

➊ First: We are going to be solving for the slope.

$m = \frac{ - 8 - 1}{5 - 2} = \frac{ - 9}{ \: \: \: 3} = - 3$

➋Second: We find the y-intercept.

$y = mx + b \\ 1 = - 3(2) + b \\ 1 = - 6 + b \\ \frac{ + 6 = + 6 \: \: \: \: \: \: \: \: \: }{7 = b}$

➌Third: Plug in.

$y = - 3x + 7$

4 0

2 years ago

Given f (x) = -3x + 4, solve for x when f (x) = 1

Solnce55 [7]

Answer:

1

Step-by-step explanation:

8 0

2 years ago

The average (arithmetic mean) of 0, a, and b is 2a. What is the value of b in terms of a?

kramer

0+a+b
a=2
b=10
0+2+10=12/3=4
4=2a
5a is the answer.

3 0

2 years ago

True or False. The point (7, 5) lies on the circle centered at the origin and containing the point (5, 2). Justify your answer.

Lina20 [59]

Answer:

the center (0.0)

radius length {5

=x^2+y^2=25

6^2+8^2

36+64

100

which is greater than 25

so Itli outside of circle

please follow me and tag me as brainlist

6 0

2 years ago

Helpi accendintly made the question I just posted 5 points but this one is 50

Umnica [9.8K]

(a) For any probability distribution, the total probability must be 1. That is, the area under the probability density curve must be equal to 1.

The empirical rule for normal distributions says

• approximately 68% of the distribution lies within 1 standard deviation of the mean

• approx. 95% lies within 2 s.d. of the mean

• approx. 99.7% lies within 3 s.d. of the mean

In this case, with mean 3500 and s.d. 470, this translates to

• Pr(3500 - 470 < X < 3500 + 470) = Pr(3030 < X < 3970) ≈ 0.68

• Pr(3500 - 2*470 < X < 3500 + 2*470) = Pr(2560 < X < 4440) ≈ 0.95

• Pr(3500 - 3*470 < X < 3500 + 3*470) = Pr(2090 < X < 4910) ≈ 0.997

Continuous probability distributions also have the property that

Pr(a < X < b) = Pr(a < X < c) + Pr(c < X < b)

if a < c < b.

Combining all these properties, we can find the probabilities for each of the 8 regions in the graph to be (from left to right)

• Pr(-∞ < X < 2090) ≈ (1 - 0.997)/2 ≈ 0.0015

• Pr(2090 < X < 2560) ≈ (1 - 0.95 - 2*0.0015)/2 ≈ 0.0235

• Pr(2560 < X < 3030) ≈ (1 - 0.68 - 2*0.0235 - 2*0.0015)/2 ≈ 0.135

• Pr(3030 < X < 3500) ≈ 0.68/2 ≈ 0.34

and since the distribution is symmetric about its mean, we already know the remaining probabilities,

• Pr(3500 < X < 3970) ≈ 0.34

• Pr(3970 < X < 4440) ≈ 0.135

• Pr(4440 < X< 4910) ≈ 0.0235

• Pr(4910 < X < ∞) ≈ 0.0015

(b) Per the rule, 99.7% of babies would weight between 2090 and 4910 grams.

(c) The proportion of babies weighing less than 3030 grams is the sum of the proportions of babies weighing less than 2090, between 2090 and 2560, and between 2560 and 3030 grams. So

Pr(X < 3030) = Pr(-∞ < X < 2090) + Pr(2090 < X < 2560) + P(2560 < X < 3030)

Pr(X < 3030) ≈ 0.0015 + 0.0235 + 0.135

Pr(X < 3030) ≈ 0.16 = 16%

(d) Similarly,

Pr(X > 2560) = Pr(2560 < X < 3030) + Pr(3030 < X < 3500) + … + Pr(4910 < X < ∞)

Pr(X > 2560) ≈ 0.135 + 0.34 + 0.34 + 0.135 + 0.0235 + 0.0015

Pr(X > 2560) ≈ 0.975 = 97.5%

8 0

2 years ago