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11111nata11111 [884]
2 years ago
10

What is the area of the rectangle?

Mathematics
1 answer:
RideAnS [48]2 years ago
7 0
  • Length=L=3cm
  • Breadth=B=2cm

Area

  • Length ×Breadth
  • 3(2)
  • 6cm²
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3x^3-2x^2-147x+98=(ax-c)(bx+d)(bx-d) where a,b,c and d positive integers. Work out the value of a,b,c and d
Alexxx [7]

Expand the right side:

(ax-c)(bx+d)(bx-d)=(ax-c)(b^2x^2-d^2)

=ab^2x^3-b^2cx^2-ad^2x+cd^2

Notice that 98 = 2 * 7 * 7, so we have c=2 and d=7.

Then

-ad^2=-147\implies a=\dfrac{147}{49}=3

and

ab^2=3\implies b^2=1\implies b=1

6 0
3 years ago
Can someone help please
Elis [28]

Answer:

Alternate

Step-by-step explanation:

Because, as you can see, it is alternating

4 0
3 years ago
On one day, 4 chefs and 5 helpers earned $650.
Arlecino [84]
4c + 5h = 650 and

5c + 6h = 800 where c are chefs, h are helpers

Start by finding an expression for c

4c + 5h = 650
4c = 650 -5h
c = (650- 5h)/4

Then substitute that into the second equation and solve for a number value for h
5 (650-5h)/4 + 6h = 800
(3250-25h)/4 + 6h = 800
Multiply both sides by 4
3250-25h + 24h = 3200
-h = -50
h = 50

Take that 50 and substitute it into the expression we have for c to get a number value for c

C= 650-5(50)/4
C = 650-250/4
C = 400/4
C= 100

Check your first equations, substituting $50 for the helpers and $100 for the chefs.

4 (100) + 5(50) =
400 + 250 = 650

5(100) + 6(50) =
500 + 300 = 800
6 0
3 years ago
If h(x) = -4x - 10, find h(-5)
Neko [114]

Answer:

zero.

Step-by-step explanation:

. Here are the steps. h(x) = -5x - 10. h(-2) = -5(-2) - 10. h(-2) = 10 - 10. h(-2) = 0. Have a great day

4 0
2 years ago
Read 2 more answers
You play two games against the same opponent. The probability you win the first game is 0.4. If you win the first game, the prob
Ilia_Sergeevich [38]

Answer:

a) No

b) 42%

c) 8%

d) X               0                 1                2

   P(X)           42%            50%         8%

e) 0.62

Step-by-step explanation:

a) No, the two games are not independent because the the probability you win the second game is dependent on the probability that you win or lose the second game.

b) P(lose first game) = 1 - P(win first game) = 1 - 0.4 = 0.6

P(lose second game) = 1 - P(win second game) = 1 - 0.3 = 0.7

P(lose both games) = P(lose first game)  × P(lose second game) = 0.6 × 0.7 = 0.42 = 42%

c)   P(win first game)  = 0.4

P(win second game) = 0.2

P(win both games) = P(win first game)  × P(win second game) = 0.4 × 0.2 = 0.08 = 8%

d) X               0                 1                2

   P(X)           42%            50%         8%

P(X = 0)  =  P(lose both games) = P(lose first game)  × P(lose second game) = 0.6 × 0.7 = 0.42 = 42%

P(X = 1) = [ P(lose first game)  × P(win second game)] + [ P(win first game)  × P(lose second game)] = ( 0.6 × 0.3) + (0.4 × 0.8) = 0.18 + 0.32 = 0.5 = 50%

e) The expected value  \mu=\Sigma}xP(x)= (0*0.42)+(1*0.5)+(2*0.08)=0.66

f) Variance \sigma^2=\Sigma(x-\mu^2)p(x)= (0-0.66)^2*0.42+ (1-0.66)^2*0.5+ (2-0.66)^2*0.08=0.3844

Standard deviation \sigma=\sqrt{variance} = \sqrt{0.3844}=0.62

8 0
3 years ago
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