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Vesna [10]
3 years ago
5

Write a word problem that can be solved using a drawing 4 x 8 ?

Mathematics
1 answer:
a_sh-v [17]3 years ago
4 0

Answer:

Bill was designing his living room. Bill decided his room was twice the size of his rug. His rug was 4x8, how big was his room.

Step-by-step explanation:

Sorry i tried.....

You might be interested in
Which of the following expressions are equivalent to 6 + (-4) - 5 ?
Gekata [30.6K]

Answer:

A

C

Step-by-step explanation:

A and C gives same result....

6 0
3 years ago
Read 2 more answers
By using a number line, arrange each of the each of the following in descending order (a) 4 29upon 33, -2.365,5.5,-3 upon 4 (b)
Sergeeva-Olga [200]

The arrangement of the numbers in descending order (largest to smallest) are as follows;

  • a). 5.5, 4, 29/33, -3/4, -2.365
  • b). 10, 5.855, 5/8, 1/2 -2π, -8

<h3>What is the arrangement of the numbers in descending order in each case?</h3>

It follows from convention that the positive numbers are larger than negative numbers and hence, should appear before negative numbers when the arrangement is in descending order.

Consequently, the numbers can be evaluated and arranged as in the answer above with positive numbers increasing rightwards and negative numbers decreasing leftward of 0 on the number line.

Read more on number line;

brainly.com/question/4619309

#SPJ1

6 0
1 year ago
hi, i dont undertand number 20 because i was absent in class today and i rerally need help, i will appraciate with the help, and
Mariulka [41]

Given:

The equation is,

2\log _3x-\log _3(x-2)=2

Explanation:

Simplify the equation by using logarthimic property.

\begin{gathered} 2\log _3x-\log _3(x-2)=2 \\ \log _3x^2-\log _3(x-2)=2_{}\text{      \lbrack{}log(a)-log(b) = log(a/b)\rbrack} \\ \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \end{gathered}

Simplify further.

\begin{gathered} \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \\ \frac{x^2}{x-2}=3^2 \\ x^2=9(x-2) \\ x^2-9x+18=0 \end{gathered}

Solve the quadratic equation for x.

\begin{gathered} x^2-6x-3x+18=0 \\ x(x-6)-3(x-6)=0 \\ (x-6)(x-3)=0 \end{gathered}

From the above equation (x - 6) = 0 or (x - 3) = 0.

For (x - 6) = 0,

\begin{gathered} x-6=0 \\ x=6 \end{gathered}

For (x - 3) = 0,

\begin{gathered} x-3=0 \\ x=3 \end{gathered}

The values of x from solving the equations are x = 3 and x = 6.

Substitute the values of x in the equation to check answers are valid or not.

For x = 3,

\begin{gathered} 2\log _3(3^{})-\log _3(3-2)=2 \\ 2\log _33-\log _31=2 \\ 2\cdot1-0=2 \\ 2=2 \end{gathered}

Equation satisfy for x = 3. So x = 3 is valid value of x.

For x = 6,

\begin{gathered} 2\log _36-\log _3(6-2)=2 \\ 2\log _36-\log _34=2 \\ \log _3(6^2)-\log _34=2 \\ \log _3(\frac{36}{4})=2 \\ \log _39=2 \\ \log _3(3^2)=2 \\ 2\log _33=2 \\ 2=2 \end{gathered}

Equation satifies for x = 6.

Thus values of x for equation are x = 3 and x = 6.

6 0
1 year ago
Algebra
vladimir2022 [97]
(2x + 3y = 12) x (-2)
(4x - 3y = 6) x 1

-4x - 6y = -24
4x - 3y = 6

You can cancel out the x values by adding the two equations together. 
(-4x + 4x) + (-6y - 3y) = (-24 + 6)
-9y = -18
y = 2

Solve for x now...
4x - 3(2) = 6
4x - 6 = 6
4x = 12
x = 3

Check... (x = 3, y = 2)
2(3) + 3(2) = 12 
6 + 6 = 12
12 = 12 <- this works! 

4(3) - 3(2) = 6
12 - 6 = 6
6 = 6 <- this works!
5 0
3 years ago
Read 2 more answers
Which of the following could be the perimeter of a rectangle with an area of 16 square inches?
Butoxors [25]

no doubt it's 16 inches

8 0
3 years ago
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