The amount of maximum mass of ethyl alcohol that could we boil with 1000 J of heat, starting from 20°C is 7.08 grams.
<h3>How do we calculate the mass?</h3>
Mass of the ethyl alcohol will be calculated by using the below equation as:
Q = mcΔT, where
- Q = absorbed heat = 1000 J
- m = mass of ethyl alcohol = ?
- c = specific heat of ethyl alcohol = 2.42 J/g.°C
- ΔT = change in temperature = (78.37°C - 20°C) = 58.37°C
On putting all these values, we get
m = 1000 / (2.42)(58.37) = 7.079 = 7.08g
Hence required mass of ethyl alcohol is 7.08grams.
To know more about absorbed heat, visit the below link:
brainly.com/question/16559442
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