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Sliva [168]
3 years ago
13

When the pressure and number of particles are kept constant for a sample of gas, which of the following is also constant for the

sample-
A) Sum of the volume and temperature

B) The difference of the volume and temperature

C) The product of the volume and temperature

D) The quotient of the volume and temperature
Chemistry
1 answer:
Leno4ka [110]3 years ago
7 0
The answer is D....................
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9966 [12]

Answer:

the agricultural revolution is the time where people went from mostly being Hunters and Gatherers to mostly farmers, a very long time ago

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3 years ago
A sample of xenon gas occupies a volume of 5.24 L at 411 K. If the pressure remains constant, at what temperature will this
stiks02 [169]

Answer:

161.57 K

Explanation:

V1/T1 = v2/T2

(5.24 L)/(411 K) = (2.06 L)/T2

T2 = 161.57 K

8 0
2 years ago
What mineral has 2 sugar-cube sized, irregularly shaped pieces. Brassy-yellow in color with metallic luster. Flat surfaces look
Vilka [71]

<u>Answer:</u>

<em>The mineral we are talking about here is olivine.</em>

<u>Explanation:</u>

It is a bit dark in color which ranges between yellow to Green to olive green. The luster present in it is nonmetallic luster but has a glassy finish and a substance hardness that is ranging between 6.5 to 7.

This mineral has granular masses which we can say has mass like sugar grains. This mineral has cleavage with conchoidal fracture present in it.

3 0
4 years ago
Crystallisation description of method<br>​
Papessa [141]

Answer:

Crystallization is a method for transforming a solution into a solid, where a supersaturated solution nucleates the solute by a chemical equilibrium controlled process. Uniform particles with well-defined morphology are formed, and these readily re-dissolve

Explanation:

3 0
3 years ago
Read 2 more answers
The acidic ingredient in vinegar is acetic acid. The pH of vinegar is around 2.4, and the molar concentration of acetic acid in
IrinaK [193]

Answer: The value of acid ionization constant K_a for acetic acid is 1.87\times 10^{-5}

Explanation:

CH_3COOH\rightarrow H^+CH_3COO^-

 cM              0             0

c-c\alpha        c\alpha          c\alpha  

So dissociation constant will be:

K_a=\frac{(c\alpha)^{2}}{c-c\alpha}

Give c= 0.85 M and pH = 2.4

pH=-log[H^+]

[H^=}=c\times \alpha=10^{-2.4}=3.98\times 10^{-3}

K_a=?

Putting in the values we get:

K_a=\frac{(3.98\times 10^{-3})^2}{(0.85-3.98\times 10^{-3})}=1.87\times 10^{-5}

Thus the value of acid ionization constant K_a for acetic acid is 1.87\times 10^{-5}

5 0
3 years ago
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