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3 years ago

13

When the pressure and number of particles are kept constant for a sample of gas, which of the following is also constant for the

sample-
A) Sum of the volume and temperature

B) The difference of the volume and temperature

C) The product of the volume and temperature

D) The quotient of the volume and temperature

1 answer:

Leno4ka [110]3 years ago

7 0

The answer is D....................

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Table sugar also consists of glucose, which is the main energy source for your body’s cells.

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2 years ago

If 3.0 g of NH3 reacts with 5.0 g of HCl, what is the limiting reactant?

ELEN [110]

<h2>Answer:HCl</h2>

Explanation:

$\text{number of moles}=\frac{\text{given mass}}{\text{molar mass}}$

For $NH_{3},$

$\text{given mass}=3g$

$\text{molar mass}=14+3=17g$

$n_{NH_{3}}=\frac{3}{17}=0.176$

For $HCl,$

$\text{given mass}=5g$

$\text{molar mass}=1+35.5=36.5g$

$n_{HCl}=\frac{5}{36.5}=0.136$

The reaction between $NH_{3}$ and $HCl$ is

$NH_{3}+HCl$ → $NH_{4}Cl$

So,one mole of $NH_{3}$ requires one mole of $HCl$

$0.176$ moles of $NH_{3}$ requires $0.176$ moles of $HCl$

But there are only $0.136$ moles of $HCl$ available.

$HCl$ will be consumed first.

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3 years ago

Using the example in the above information determine the empirical formula of a compound if a sample contains 0.130 g of nitroge

olga2289 [7]

Answer: The empirical formula for the given compound is $NO_2$

Explanation : Given,

Mass of O = 0.370 g

Mass of N = 0.130 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.370g}{16g/mole}=0.0231moles$

Moles of Nitrogen = $\frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{0.130g}{14g/mole}=0.00928moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.00928 moles.

For Oxygen = $\frac{0.0231}{0.00928}=2.4\approx 2$

For Nitrogen = $\frac{0.00928}{0.00928}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of O : N = 2 : 1

Hence, the empirical formula for the given compound is $NO_2$

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