Question

Using factoring, which values are the solutions to the quadratic equation 2m2+7m−30=0?

Answer 1

Answer:

B: m = -6 or m = 5/2

Explanation:

$\rightarrow \sf 2m^2 +7m - 30 = 0$

breakdown

$\rightarrow \sf 2m^2 +12m -5m- 30 = 0$

take out common factor

$\rightarrow \sf 2m(m +6) -5(m+ 6) = 0$

collect into groups

$\rightarrow \sf (2m -5)(m+ 6) = 0$

set to zero

$\rightarrow \sf 2m -5=0, \ m+ 6 = 0$

change sides

$\rightarrow \sf m=2.5, \ m= -6$

Answer 2

Answer:

$\sf B. \quad m=-6 \quad or \quad m=\dfrac{5}{2}$

Step-by-step explanation:

Given equation:

$\sf 2m^2+7m-30=0$

Factor:

$\implies \sf 2m^2+12m-5m-30=0$

$\implies \sf 2m(m+6)-5(m+6)=0$

$\implies \sf (2m-5)(m+6)=0$

Therefore:

$\implies \sf 2m-5=0 \implies m=\dfrac{5}{2}$

$\implies \sf m+6=0 \implies m=-6$

Therefore, the solutions are:

$\sf m=-6 \quad or \quad m=\dfrac{5}{2}$