2.5 yds
C=2πr
d=2r
Solving ford
d=C
π=7.85
π≈2.
Step-by-step explanation:
<h3><em>Explanation</em><em> </em><em>is </em><em>in</em><em> the</em><em> </em><em>attachment</em><em> </em></h3>
<em>Hope </em><em>it</em><em> is</em><em> helpful</em><em> to</em><em> you</em>
The answer is 20000000+600000+30000+7000+100+30+9
(a) Compare your quadratic for h to the general quadratic ax² +bx +c. Perhaps you can see that ...
a = -16
b = 128
You use these numbers in the given formula to find the time when the ball is highest.
t = -b/(2a) = -128/(2(-16)) = 4 . . . . . . the time at which the ball is highest
(b) Evaluate the quadratic to find the height at t=4.
h = -16(4)² +128(4) +21
h = -256 +512 +21
h = 277
The maximum height of the ball is 277 ft.