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MatroZZZ [7]
3 years ago
6

The histogram shows the number of minutes people were required to wait when they went to register for school. How many users are

represented in the graph?

Mathematics
2 answers:
UkoKoshka [18]3 years ago
7 0

Answer:

4

Step-by-step explanation:

60 minutes = 1 hour → 120 minutes = 2 hours. The purple bar represents at least 121 minutes, which is greater than 2 hours.

Margaret [11]3 years ago
6 0

Answer: should be 24 people.

Step-by-step explanation: first bar is 5 people, next one is 4, then 9, and 2, then 4

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PLEASE HELPPPPL!!!
KiRa [710]

Answer:

(0,1) (0.333,0)

(7,0)

m=1

Step-by-step explanation:

4 0
3 years ago
Suppose that an angle is bisected to form two smaller angles that measure (2+30)° and (8+6)° . What is the measure of the origin
Valentin [98]

M<A=(2+30)  M<B=(8+6)

(2+30)+(8+6)

32+14

46

M<A+B=46

Answer: The original angle measured 46 Degrees

6 0
2 years ago
How many different linear arrangements are there of the letters a, b,c, d, e for which: (a a is last in line? (b a is before d?
inna [77]
A) Since a is last in line, we can disregard a, and concentrate on the remaining letters.
Let's start by drawing out a representation:

_ _ _ _ a

Since the other letters don't matter, then the number of ways simply becomes 4! = 24 ways

b) Since a is before d, we need to account for all of the possible cases.

Case 1: a d _ _ _ 
Case 2: a _ d _ _
Case 3: a _ _ d _
Case 4: a _ _ _ d

Let's start with case 1.
Since there are four different arrangements they can make, we also need to account for the remaining 4 letters.
\text{Case 1: } 4 \cdot 4!

Now, for case 2:
Let's group the three terms together. They can appear in: 3 spaces.
\text{Case 2: } 3 \cdot 4!

Case 3:
Exactly, the same process. Account for how many times this can happen, and multiply by 4!, since there are no specifics for the remaining letters.
\text{Case 3: } 2 \cdot 4!

\text{Case 4: } 1 \cdot 4!

\text{Total arrangements}: 4 \cdot 4! + 3 \cdot 4! + 2 \cdot 4! + 1 \cdot 4! = 240

c) Let's start by dealing with the restrictions.
By visually representing it, then we can see some obvious patterns.

a b c _ _

We know that this isn't the only arrangement that they can make.
From the previous question, we know that they can also sit in these positions:

_ a b c _
_ _ a b c

So, we have three possible arrangements. Now, we can say:
a c b _ _ or c a b _ _
and they are together.

In fact, they can swap in 3! ways. Thus, we need to account for these extra 3! and 2! (since the d and e can swap as well).

\text{Total arrangements: } 3 \cdot 3! \cdot 2! = 36
7 0
3 years ago
How many liters of water is there in a fish tank with dimensions 25cm by 20cm by 10cm
tekilochka [14]

Answer: 5000cm

Step-by-step explanation: 25cm x 20cm x 10cm

hope this helps :)

7 0
2 years ago
The length of a ribbon is 6/7 meter. Sun Yi needs pieces measuring 1/6 meter for an art project. What is the greatest number of
Strike441 [17]

Answer:

Let's find out!

Step-by-step explanation:

So we have to set up an equation

Let x= # of ribbons that can be cut

Thus:

\frac{1}{6}x =\frac{6}{7} \\x=\frac{6}{7} *\frac{6}{1} \\x=\frac{36}{7}

So, we cannot have 36/7 ribbons! It's not possible!

So we just simplify!

x=5\frac{1}{7}

There we go! She can cut 5 ribbons off!

I'll let you figure out the last one!

Hope this helps!

P.S. Stay Safe!

6 0
3 years ago
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