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MatroZZZ [7]
3 years ago
6

The histogram shows the number of minutes people were required to wait when they went to register for school. How many users are

represented in the graph?

Mathematics
2 answers:
UkoKoshka [18]3 years ago
7 0

Answer:

4

Step-by-step explanation:

60 minutes = 1 hour → 120 minutes = 2 hours. The purple bar represents at least 121 minutes, which is greater than 2 hours.

Margaret [11]3 years ago
6 0

Answer: should be 24 people.

Step-by-step explanation: first bar is 5 people, next one is 4, then 9, and 2, then 4

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Out of 400 applicants for a job, 179 are female and 72 are female and have a graduate degree. Step 2 of 2 : If 118 of the applic
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Answer:

36/59 or 0.610

Step-by-step explanation:

P(female and degree)/P(degree)

72/118

36/59

0r 0.610

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Thank me later,or dont thank me at all

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Jimmy does yard work around his neighborhood. In a given week he works at least two days, but no more than five. And on the days
Allushta [10]
<span>the answer is D. 6≤M≤856≤M≤85</span>
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3 years ago
If Dave runs 1.8 kilometers in the 15 minutes, what is his average rate
sladkih [1.3K]

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.12 km/min.

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3 0
3 years ago
An airport limousine can accommodate up to four passengers on any one trip. The company will accept a maximum of six reservation
miss Akunina [59]

Answer:

a) 0.109375 = 0.109 to 3 d.p

b) 1.00 to 3 d.p

Step-by-step explanation:

Probability of someone that made a reservation not showing up = 50% = 0.5

Probability of someone that made a reservation showing up = 1 - 0.5 = 0.5

a) If six reservations are made, what is the probability that at least one individual with a reservation cannot be accommodated on the trip?

For this to happen, 5 or 6 people have to show up since the limousine can accommodate a maximum of 4 people

Let P(X=x) represent x people showing up

probability that at least one individual with a reservation cannot be accommodated on the trip = P(X = 5) + P(X = 6)

P(X = x) can be evaluated using binomial distribution formula

Binomial distribution function is represented by

P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ

n = total number of sample spaces = 6

x = Number of successes required = 5 or 6

p = probability of success = 0.5

q = probability of failure = 0.5

P(X = 5) = ⁶C₅ (0.5)⁵ (0.5)⁶⁻⁵ = 6(0.5)⁶ = 0.09375

P(X = 6) = ⁶C₆ (0.5)⁶ (0.5)⁶⁻⁶ = 1(0.5)⁶ = 0.015625

P(X=5) + P(X=6) = 0.09375 + 0.015625 = 0.109375

b) If six reservations are made, what is the expected number of available places when the limousine departs?

Probability of one person not showing up after reservation of a seat = 0.5

Expected number of people that do not show up = E(X) = Σ xᵢpᵢ

where xᵢ = each independent person,

pᵢ = probability of each independent person not showing up.

E(X) = 6(1×0.5) = 3

If 3 people do not show up, it means 3 people show up and the number of unoccupied seats in a 4-seater limousine = 4 - 3 = 1

So, expected number of unoccupied seats = 1

5 0
3 years ago
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