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2 years ago

Can someone help me will mark brainlist

Mathematics

1 answer:

Nana76 [90]2 years ago

5 0

Answer:

D) -4, 0

Step-by-step explanation:

find common difference.

the common difference appears to be +4 as you must add 4 to -12 to get to -8

now we find the missing terms.

the previous term of the first missing term is -8

if the common difference is +4 then the next term would be -8 + 4 = -4

the term after that would be -4 + 4 = 0

the two missing terms are -4 and 0

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2.48030477 rounded to the nearest hundred-thousandth is

ValentinkaMS [17]

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3 years ago

Write a vector equation of the line that passes through p(–1 6) and is parallel to a = (3, -1).

Phoenix [80]

Answer:

Step-by-step explanation:

(x,y) = p + t(a)

(x,y) = (-1,6) + t(3,-1)

(x,y) - (-1,6) = t(3,-1)

(x + 1, y - 6) = t(3, -1)

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3 years ago

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There are 48 boys and 64 girls in the choir. What is the greatest amount of rows that can be created in which the same number of

nordsb [41]

48: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48

64: 1, 2, 4, 8, 16, 32, 64

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3 years ago

Read 2 more answers

I’ll give brainliest!!!!! Pls help ASAP

storchak [24]

Answer:

$\sqrt[4]{x^{7} }$

Step-by-step explanation:

this is the same concept basically as simplifying $\sqrt{x}$ into $x^{\frac{1}{2} }$ . You can see that the denominator is in front of the radical and that any numbers in the numerator are the power of the number underneath.

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3 years ago

The probability of an event - picking teams. About (a) 10 kids are randomly grouped into an A team with five kids and a B team w

LuckyWell [14K]

Answer: The required probability is $\dfrac{4}{9}$

Step-by-step explanation:

Since we have given that

Number of kids = 10

Number of kids in Team A = 5

Number of kids in Team B = 5

There are three kids in the group, Alex and his two best friends Jose and Carl.

So, number of favourable outcome is given by

$2(\dfrac{8!}{3!\times 5!})$

Total number of outcomes is given by

$\dfrac{10!}{5!\times 5!}$

So, the probability that Alex ends up on the same team with at least one of his two best friends is given by

$\dfrac{2(\dfrac{8!}{5!\times 3!)}}{\dfrac{10!}{5!\times 5!}}\\\\=2\times \dfrac{8!}{3!}\times \dfrac{5!}{10!}\\\\=\dfrac{4}{9}$

Hence, the required probability is $\dfrac{4}{9}$

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3 years ago