Write an equation in point-slope form for the line that has a slope of 45 and contains the point (−5,−3).
1 answer:
Answer:
y+3=45(x+5)
Step-by-step explanation:
Hi there!
Point-Slope Form:
y-y1=m(x-x1)
Where
y1 stands for the y-coordinate of the point
m stands for the slope of the line
x1 stands for the x-coordinate of the point
In this case, the slope is 45, the y-coordinate of the given point is -3, and the x-coordinate of the point is -5.
Plug in the values and solve:
y-y1=m(x-x1)
y-(-3)=45(x-(-5)
y+3=45(x+5)
Hope it helps!
Enjoy your day!
Please feel free to ask if you have any doubts.
You might be interested in
Answer:
In the given equation -14(3a+6)=12(6-4a)+12 the value of a is 28
Step-by-step explanation:
Given equation is -14(3a+6)=12(6-4a)+12
To simplify the given equation:
-14(3a+6)=12(6-4a)+12
Taking all terms to one side
-14(3a+6)-12(6-4a)-12=0
-[14(3a+6)+12(6-4a)+12]=0
Now dividing by negative sign on the above equation we get
14(3a+6)+12(6-4a)+12=0 (using distributive property)
42a+84+72-48a+12=0 ( adding the like terms )
-6a+168=0
-6a=-168
6a=168
Therefore a=28
Therefore in the given equation -14(3a+6)=12(6-4a)+12 the value of a is 28