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andriy [413]
2 years ago
15

I need help plssssss

Mathematics
1 answer:
Ymorist [56]2 years ago
5 0

Answer:

36cm^2

Step-by-step explanation:

you multiply base times height or length times width to get area

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Which polynomial shows the difference of (4x2 + 3x - 2) and (x2 + 2x + 4)?
Marat540 [252]

Answer:

b

Step-by-step explanation:

3 0
3 years ago
The price of a house decreased from $500,000 to $400,000 in one year. What is the percent decrease?
-BARSIC- [3]

Answer:

A) 20%

Step-by-step explanation:

A) ✅

500000(0.2) = 100,000

500000 - 100,000 = 400,000

B) ❌

500000(0.25) = 125,000

500000 - 125,000 = 375,000

C) ❌

500000(0.3) = 150,000

500000 - 150,000 = 350,000

D) ❌

500000(0.35) = 175,000

500000 - 175,000 = 325,000

6 0
3 years ago
Read 2 more answers
The spinner below is spun twice. What is the probability of the arrow landing on a 3 and then an odd number?
Mice21 [21]

Answer:

4/3

Step-by-step explanation:

6 0
3 years ago
18 Ib= oz plz help me mann
Nataliya [291]
There are 288 ounces in 18 lbs
6 0
3 years ago
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An urn contains nine red and one blue balls. A second urn contains one red and five blue balls. One ball is removed from each ur
il63 [147K]

Answer:

0.362

Step-by-step explanation:

When drawing randomly from the 1st and 2nd urn, 4 case scenarios may happen:

- Red ball is drawn from the 1st urn with a probability of 9/10, red ball is drawn from the 2st urn with a probability of 1/6. The probability of this case to happen is (9/10)*(1/6) = 9/60 = 3/20 or 0.15. The probability that a ball drawn randomly from the third urn is blue given this scenario is (1 blue + 5 blue)/(8 red + 1 blue + 5 blue) = 6/14 = 3/7.

- Red ball is drawn from the 1st urn with a probability of 9/10, blue ball is drawn from the 2nd urn with a probability of 5/6. The probability of this event to happen is (9/10)*(5/6) = 45/60 = 3/4 or 0.75. The probability that a ball drawn randomly from the third urn is blue given this scenario is (1 blue + 4 blue)/(8 red + 1 blue + 1 red + 4 blue) = 5/14

- Blue ball is drawn from the 1st urn with a probability of 1/10, blue ball is drawn from the 2nd urn with a probability of 5/6. The probability of this event to happen is (1/10)*(5/6) = 5/60 = 1/12. The probability that a ball drawn randomly from the third urn is blue given this scenario is (4 blue)/(9 red + 1 red + 4 blue) = 4/14 = 2/7

- Blue ball is drawn from the 1st urn with a probability of 1/10, red ball is drawn from the 2st urn with a probability of 1/6. The probability of this event to happen is (1/10)*(1/6) = 1/60. The probability that a ball drawn randomly from the third urn is blue given this scenario is (5 blue)/(9 red + 5 blue) = 5/14.

Overall, the total probability that a ball drawn randomly from the third urn is blue is the sum of product of each scenario to happen with their respective given probability

P = 0.15(3/7) + 0.75(5/14) + (1/12)*(2/7) + (1/60)*(5/14) = 0.362

8 0
3 years ago
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