3 years ago

a trapezoid has an area of 30 in2. if the lengths of the bases are 4.8 in and 5.2 in, what is the height?

Mathematics

1 answer:

DaniilM [7]3 years ago

4 0

30*2= (4.8+5.2)h
60=10h
h=10

height= 10 inches

You might be interested in

Solve the quadratic equation 2x^2 + 6 = 8x by graphing.

Semmy [17]

Answer:

D is the right ans after solving eqn we get two value of x and they are 1 and 3

3 0

2 years ago

Use Newton's method to approximate the roots<br> of f(x) = 3x3 – 4x2 + 1 to six digits.

laila [671]

Answer:

Step-by-step explanation:

6 0

3 years ago

What is the distance between (22,-3) and (1, -3)?

Bingel [31]

Answer:

Option D

Step-by-step explanation:

<h2>Distance between two points</h2>

The y-value of the two points is unchanged. So, the line is parralel to x-axis.

The distance will be the diffrence between the x-co ordinates.

$\sf Distance = 1 - (-2\dfrac{1}{2})$

$\sf =1+\dfrac{5}{2}\\\\= \dfrac{2}{2}+\dfrac{5}{2}\\\\=\dfrac{7}{2}\\\\=3\dfrac{1}{2}$

6 0

2 years ago

In the diagram below, AB = BD = BC, and mZA = 24°. Find<br> mZC.

snow_tiger [21]

Answer:

m∠C = 66°

Step-by-step explanation:

Since AB = BD, it means this triangle is an Isosceles triangle and as such;

∠BAD = ∠BDA = 24°

Thus, since sum of angles in a triangle is 180,then;

∠ABD = 180 - (24 + 24)

∠ABD = 180 - 48

∠ABD = 132°

We are told that BC = BD.

Thus, ∆BDC is an Isosceles triangle whereby ∠BCD = ∠BDC

Now, in triangles, we know that an exterior angle is equal to the sum of two opposite interior angles.

Thus;

132 = ∠BCD + ∠BDC

Since ∠BCD = ∠BDC, then

∠BCD = ∠BDC = 132/2

∠BCD = ∠BDC = 66°

3 0

3 years ago

Im stuck lol, I'm doing algebra 1, the answer is supposed to be <br><img src="https://tex.z-dn.net/?f=27%20%5Cfrac%7B3%7D%7B8%7D

maxonik [38]

$27.37

...................

4 0

4 years ago