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2 years ago

Use the data set to answer the question. PLS NEED HELP!! No files or links please! :))

Mathematics

1 answer:

coldgirl [10]2 years ago

6 0

$\bold{ANSWER:}$
46.5

$\bold{EXPLANATIONS:}$

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Please answer all of them

kondaur [170]

Answer:

a. x = 5/2

b. y = 16.5

c. z = 12

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

(-6,8); perpendicular to y = -3/2x -1

UNO [17]

Answer:

$y = \frac{2}{3} x + 12$

Step-by-step explanation:

$y = - \frac{3}{2} x - 1$

The gradient of a line is the coefficient of x when the equation of the line is written in the form of y=mx+c.

Thus, gradient of given line= $- \frac{3}{2}$ .

The product of the gradients of perpendicular lines is -1.

(Gradient of line)(-3/2)= -1

Gradient of line

$- 1 \div ( - \frac{3}{2} ) \\ = - 1( - \frac{2}{3} ) \\ = \frac{2}{3}$

Substitute m= $\frac{2}{3}$ into y=mx+c:

$y = \frac{2}{3} x + c$

To find the value of c, substitute a pair of coordinates.

When x= -6, y= 8,

$8 = \frac{2}{3} ( - 6) + c \\ \\ 8 = - 4 + c \\ c = 8 + 4 \\ c = 12$

Thus, the equation of the line is $y = \frac{2}{3} x + 12$ .

7 0

3 years ago

Simplify -23b4+(-7b4)

Rzqust [24]

-30b4 would be your answer.

Hope I helped!

3 0

3 years ago

What is the length of the longest side of a triangle that has vertices at (-2,6) (-4,6) and (-4,4)?

zalisa [80]

Length (2, 6) to (-4, 6) is sqrt((x2 - x1))^2 + (y2 - y1)^2) = sqrt((-4 -2)^2 + (6 - 6)^2) = sqrt((-6)^2 + 0) = 6

Length (2, 6) to (-4, 4) is sqrt((-4 - 2)^2 + (4 - 6)^2) = sqrt((-6)^2 + (-2)^2) = sqrt(36 + 4) = sqrt(40) = 2sqrt(10) units

Length (-4, 6) to (-4, 4) is sqrt((-4 - (-4))^2 + (4 - 6)^2) = sqrt(0^2 + (-2)^2) = 2

So the length of the longest side is 2sqrt(10) units

6 0

3 years ago

Simplify the expression:<br><br>(6 + 8) + x = 14

Alex787 [66]

Answer:

x=0 is your answer

Step-by-step explanation:

(6 + 8) + x = 14

14+x=14

x=14-14

x=0

5 0

3 years ago

Read 2 more answers