Answer:
Step-by-step explanation:
The student hasn't finished the factoring yet.
<u>He still needs the step:</u>
<u>The next step:</u>
- 0 = 2x + 5, 0 = x + 1
- x = - 2.5, x = - 1
Answer:
33.3 % (Approx) percent of fish that Tom’s caught of the number of fish his son caught .
25% is the percent of the total amount Tom caught.
Step-by-step explanation:
Formula

Part First
As given
Tom caught 4 fish and his son caught 12 fish.
Here
Part value = 4
Total value = 12
Put in the formula


Percentage = 33.3 % (Approx)
Therefore the 33.3 % (Approx) percent of fish that Tom’s caught of the number of fish his son caught .
Second Part
As given
Tom caught 4 fish and his son caught 12 fish.
Total number of fish caught = 4 + 12
= 16
Part value = 4
Total value = 16
Put in the formula


Percentage = 25%
Therefore the 25% is the percent of the total amount Tom caught.
Salutations!
<span>The ratio of boys to girls in a school is 5:4. if there are 180 students, how many girls are there?
Let the number of girls and boys be 'x'.
</span>

<span>
Add 5 and 4
</span>

<span>
</span>

<span>
Now, multiply the ratios by 20.
Boys =
20 </span>× 5 = 100
Girls = 20 × 4 = 80.
There were 80 girls.
Hope I helped (:
Have a great day!
Answer: 8/5
Step-by-step explanation: I hope this helps!!!!
When you add the equations in (a) you get 7x+y=24.
When you subtract the equations in (b) you also get 7x+y=24.
That means to solve both systems you can work with the same equation. However that is not enough. We must have two equivalent equations. We found only one.
Notice however that in the (b) we can take the first equation and divide every term by 2. When we do this we get 4x-5y=13. That’s the first equation in (a).
So both systems can be solved by working with the same two equations. These are 5x-5y=13 and 7x+y=24. And since we have two equations and two unknowns (the number of equations matches the number of variables) there is only one solution — one x and y that would make both systems true — solve both systems.
Basically we showed the systems are equivalent!