<u>Part a)</u> if a page is reduced to 80%, what percent enlargement is needed to return it to its original size?
Let
x---------> the percent enlargement
we know that
the original size is the 100%
so
x*80%=100%
x=(100%/80%)
x=1.25--------> 1.25=(125/100)=125%
therefore
<u>the answer Part a) is</u>
the percent enlargement is 125%
<u>Part b)</u> Estimate the number of times in succession that a page must be copied to make the final copy less than 15% of the size of the original
we know that
A photocopy machine can reduce copies to 80% of their original size
so
Copy N 1
0.80*100%=80%
Copy N 2
0.80*80%=64%
Copy N 3
0.80*64%=51.2%
Copy N 4
0.80*51.2%=40.96%
Copy N 5
0.80*40.96%=32.77%
Copy N 6
0.80*32.77%=26.21%
Copy N 7
0.80*26.21%=20.97%
Copy N 8
0.80*20.97%=16.78%
Copy N 9
0.80*16.78%=13.42%-------------> 13.42% < 15%
therefore
<u>the answer Part b) is</u>
the number of times in succession is 9
Answer:
2(3 - 2d)
Step-by-step explanation:
All you need to do is factor out 2 from the original expression, so 6 - 4d.
Answer:
0.979%
Step-by-step explanation:
Given that:
Estimated value = 825 ;
Actual value = 817
Percentage error:
(|Estimated value - Actual value| ÷ actual value) * 100%
(|825 - 817| ÷ 817) * 100%
(8 / 817) * 100%
0.0097919 * 100%
= 0.979%
= 1% (nearest percent)
Answer:
A
Step-by-step explanation:
Answer:
If A and B are vertical angles, then they are congruent, so their measures are equal.
This means
(5x + 5)º = (4x + 29)º
5x + 5 = 4x + 29
x = 24
Then angle A has measure (5*24 + 5)º = 125º.
Step-by-step explanation:
