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andre [41]
2 years ago
10

A personal trainer determines that an individual will get the most benefit from a workout if they keep their heart rate at an av

erage of 150 beats per minute during workouts. To determine if the individual is doing so successfully, a random sample of 30 workouts is selected from their fitness watch. A 95% confidence interval for these workouts reveals that the true mean heart rate while working out is between 158 and 167 beats per minute. Based upon this interval, what conclusion should be made about the hypotheses: H Subscript 0 Baseline: mu = 150 versus H Subscript alpha Baseline: mu not-equals150 where μ = this individual’s true mean heart rate during working out at α = 0.05?
Reject H0. There is convincing evidence that the mean heart rate from these 30 workouts differs from 150.
Reject H0. There is convincing evidence that this individual’s true mean heart rate while working out differs from 150.
Fail to reject H0. There is not convincing evidence that the mean heart rate from these 30 workouts differs from 150.
Fail to reject H0. There is not convincing evidence that this individual’s true mean heart rate while working out differs from 150.
Mathematics
1 answer:
Korvikt [17]2 years ago
6 0

Using the confidence interval, it is found that the correct conclusion regarding the hypotheses test is given by:

Reject H0. There is convincing evidence that this individual’s true mean heart rate while working out differs from 150.

<h3>What are the hypotheses tested?</h3>

At the null hypotheses, it is tested if the mean is of 150, that is:

H_0: \mu = 150

At the alternative hypotheses, it is tested if the mean is different of 150, hence:

H_0: \mu \neq 150.

The confidence interval is (158, 167). Since it does not contain 150, we reject the null hypotheses, hence the correct option is:

Reject H0. There is convincing evidence that this individual’s true mean heart rate while working out differs from 150.

More can be learned about confidence intervals at brainly.com/question/25890103

#SPJ1

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Setler [38]
Car 1
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40 miles..........................20 minutes
car2
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30 miles...........................20 minutes
the difference is 0.5 miles per minute

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Is the mean value theorem for integrals the same as the mean value thoerem for derivatives?
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3 0
3 years ago
Ivy is trying to manage the money she spends on lunch. Between eating out and buying groceries for bagged lunches, she wants to
mr_godi [17]

Answer:

The monetary choices for Ivy’s lunches is to spend less than $16.67 at restaurants and to spend less than $33.33 on groceries in order to to keep her weekly budget to less than $50.

Step-by-step explanation:

This can be determined as follows

x = the amount of dollars spent at restaurants

y = the amount of dollars spent on groceries

Since Ivy decides that she wants to spend at least twice as much on bagged lunches as at restaurants, we have

y = 2x .................. (1)

Since Ivy wants to keep her weekly budget to less than $50, using the x and y, we have:

x + 2x < 50 ............................ (2)

We can now solve for x as follows:

3x + < 50

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x < 16.67

Substituting the x < 17 into equation (1) noting that Ivy wants to keep her weekly budget to less than $50, we have:

y < 2 * 16.67

y < 33.33

Therefore, the monetary choices for Ivy’s lunches is to spend less than $16.67 at restaurants and to spend less than $33.33 on groceries in order to to keep her weekly budget to less than $50.

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2 years ago
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