Answer:
The triangles are not similar
Step-by-step explanation:
we know that
If two triangles are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent
<em>Triangle X.Y.Z</em>


---> angle X and angle Y are complementary angles
<em>Triangle H.G.J</em>
---> angle H and angle J are complementary angles


so
X.Y.Z is a
triangle
H.G.J is a
triangle
The measure of its corresponding angles are not congruent
therefore
The triangles are not similar
Using the binomial distribution, it is found that there is a 0.0012 = 0.12% probability at least two of them make it inside the recycling bin.
<h3>What is the binomial distribution formula?</h3>
The formula is:


The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
With 5 shoots, the probability of making at least one is
, hence the probability of making none, P(X = 0), is
, hence:

![\sqrt[5]{(1 - p)^5} = \sqrt[5]{\frac{232}{243}}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B%281%20-%20p%29%5E5%7D%20%3D%20%5Csqrt%5B5%5D%7B%5Cfrac%7B232%7D%7B243%7D%7D)
1 - p = 0.9908
p = 0.0092
Then, with 6 shoots, the parameters are:
n = 6, p = 0.0092.
The probability that at least two of them make it inside the recycling bin is:

In which:
[P(X < 2) = P(X = 0) + P(X = 1)
Then:



Then:
P(X < 2) = P(X = 0) + P(X = 1) = 0.9461 + 0.0527 = 0.9988

0.0012 = 0.12% probability at least two of them make it inside the recycling bin.
More can be learned about the binomial distribution at brainly.com/question/24863377
#SPJ1
0.300 + .020 + 0.006 would be 0.326 in expanded form.
Answer:
°
Step-by-step explanation:
"Theorem 9-13: The measure of an angle formed by two secants, two tangents, or a secant and a tangent drawn from a point outside the circle is equal to half the difference of the measures of the intercepted arcs."
Basically no matter what other circle, secant or tangent you get, you just use the formula
If you need the outer angle, just put the other angles in and solve
If you need the far or near point angle, re-arrange the formula to get that value.