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3 years ago

Are -3.9 and -0.99 on the same side or the opposite side of zero ?

2 answers:

6 0

Same side. Locate -3.9 on the number line. Then -0.99 is to the right of -3.9, with both numbers being on the same side (that is, on the left side) of zero.

Evgesh-ka [11]3 years ago

4 0

Same side, think of it as a number line. there is a left side for negitives, and a right for positives. Every negitive number is on the same side, while the positives have their own side too. Only if it was a positive with a negitive it would be on opposite sides.

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which expression is equivalent to (^3sqrtm)^7 in exponential form? a) 7 m/3 b) 3 m/7 c) m 3/7 d) m 7/3

Komok [63]

$(\sqrt[3]{m})^{7} = m^{ \frac{7}{3}}$

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2 years ago

QUESTION:-

avanturin [10]

Answer:

pic attached

Step-by-step explanation:

hope it helps..

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2 years ago

A garden table and a bench cost $770 combined. The garden $ 80 table costs less than the bench. What is the cost of the bench?

aleksklad [387]

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3 years ago

The midpoint of the coordinates (3, 15) and (20,8) is -

Nat2105 [25]

Answer:

The midpoint of the given coordinates is $(\frac{23}{2},\frac{23}{2})\ or\ (11.5,11.5)$ .

Step-by-step explanation:

We have given two coordinates (3,15) and (20,8).

Let we have given a line segment PQ whose P coordinate is (3,15) and Q coordinate is (20,8).

We have to find out the mid point M(x,y) of the line segment PQ.

Solution,

By the mid point formula of coordinates, which is;

$(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

On substituting the given values, we get;

$M(x,y)=(\frac{3+20}{2}, \frac{15+8}{2})\\\\M(x,y)=(\frac{23}{2},\frac{23}{2})$

We can also say that $M(x,y)=(11.5,11.5)$

Hence The midpoint of the given coordinates is $(\frac{23}{2},\frac{23}{2})\ or\ (11.5,11.5)$ .

3 0

3 years ago

How do i get the solution to graph 2x+3y=12

Pavel [41]

2x + 3y = 12

I am going to put this in y = mx + b form, where m is ur slope and b is ur y intercept.
2x + 3y = 12
3y = -2x + 12
y = -2/3x + 4......slope is -2/3 and y int is (0,4)

x int can be found by subbing in 0 for y and solving for x
2x + 3y = 12
2x + 3(0) = 12
2x = 12
x = 6.....so x int is (6,0)

start at y int (0,4).....and since the slope is -2/3, come down 2 spaces, and to the right 3 spaces, then down 2 spaces, to the right 3 spaces....keep doing that and u should cross the x axis at (6,0)

7 0

3 years ago