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Pavlova-9 [17]
3 years ago
11

3. Valentina and Chloe were standing next to each other. Chloe walked south for 86 meters

Mathematics
1 answer:
mamaluj [8]3 years ago
3 0

Answer:

86 meters was back on valentina,

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-3(8+j)=-16+5j<br> HELP ASAP NEED THIS DONE TONIGHT BEFORE MIDNIGHT
iogann1982 [59]

Answer:

  j = -1

Step-by-step explanation:

Eliminate parentheses:

  -24 -3j = -16 +5j

Add 3j+16

  -8 = 8j

Divide by the coefficient of j.

  -1 = j

8 0
3 years ago
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Astronauts who traveled to the moon were able to float slightly as they walked along its surface. Why wee the astronauts able to
Alex_Xolod [135]

Answer:

C.

Step-by-step explanation:

the farther you get from Earth, the less the gravitational force i, so if your in space,<em><u> </u></em><em><u>you will have more weight next to earth than you will next to the moon</u></em><em><u>.</u></em>

7 0
3 years ago
Arrange the following set of decimal numbers in order from smallest to largest.
Setler [38]

Answer:

Step-by-step explanation:

0.31=0.3100

0.409=0.4090

0.414=0.4140

0.4186

arranging smallest to largest

0.3100,0.4090,0.4140,0.4186

or 0.31,0.409,0.414,0.4186

6 0
4 years ago
Please find the value of x please
marin [14]
Answer is 7

Step by step explanation

3x+159=180
3x=180-159=21
x=7
5 0
3 years ago
Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round y
kupik [55]

Answer:

75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5 pounds.

Step-by-step explanation:

The question is missing. It is as follows:

Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains had the following weights (pounds): 69  104  125  129  60  64

Assume that the population of x values has an approximately normal distribution.

Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round your answers to one decimal place.)

75% Confidence Interval can be calculated using M±ME where

  • M is the sample mean weight of the wild mountain lions (\frac{69 +104 +125 +129+60 +64}{6} =91.8)
  • ME is the margin of error of the mean

And margin of error (ME) of the mean can be calculated using the formula

ME=\frac{t*s}{\sqrt{N} } where

  • t is the corresponding statistic in the 75% confidence level and 5 degrees of freedom (1.30)
  • s is the standard deviation of the sample(31.4)
  • N is the sample size (6)

Thus, ME=\frac{1.30*31.4}{\sqrt{6} } ≈16.66

Then 75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5

3 0
3 years ago
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