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notsponge [240]
2 years ago
14

Pls help! Due soon!!

Mathematics
1 answer:
bogdanovich [222]2 years ago
3 0

Answer:

See below ~

Step-by-step explanation:

1. 3d + 2

2. John = Kelly - 6

3. y/4 - 3

4. Thomas = 2(Luis)

5. 8p + 6

6. x³ + 5

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A line passes through (10,4) and (13,-11). Write the equation of the line in standard form.
AlexFokin [52]

\bf (\stackrel{x_1}{10}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{13}~,~\stackrel{y_2}{-11}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-11-4}{13-10}\implies \cfrac{-15}{3}\implies -5 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-4=-5(x-10)


now

standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

therefore,


\bf y-4=-5(x-10)\implies y-4=-5x+50\implies \blacktriangleright 5x+y=54 \blacktriangleleft

7 0
3 years ago
Two events, X and Y, are independent of each other. P(Y) = 5/6 and P(X and Y) = 1/3. What is P(X) written as a decimal? Round to
Ksenya-84 [330]
For independent events,
P(X ∩ Y) = P(X)* P(Y)
=>
1/3 = P(X)*(5/6)
solve for P(X) =>
P(X) = (1/3)*(6/5) = 2/5 = 0.4
5 0
3 years ago
Read 2 more answers
What is the range for the function f(x)=^3/×
Galina-37 [17]
M=ch x 4 next 3 = mch (34)
5 0
3 years ago
Find the value of given expression<br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B213%20%5Ctimes%20213%7D%20" id="TexForm
Hatshy [7]

Answer:

213 Answer ..............

7 0
3 years ago
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We roll a fair die repeatedly until we see the number four appear and then we stop. The outcome of the experiment is the number
muminat

Answer:

0

Step-by-step explanation:

given that we roll a fair die repeatedly until we see the number four appear and then we stop.

the number 4 can appear either in I throw, or II throw or .... indefinitely

So X = the no of throws can be from 1 to infinity

This is a discrete distribution countable.

Sample space= {1,2,.....}

b) Prob ( 4 never appears) = Prob (any other number appears in all throws)

= \frac{5}{6} *\frac{5}{6} *\frac{5}{6} *\frac{5}{6} *...\\=(\frac{5}{6} )^n

where n is the number of throws

As n tends to infinity, this becomes 0 because 5/6 is less than 1.

Hence this probability is approximately 0

Or definitely 4 will appear atleast once.

8 0
3 years ago
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