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3 years ago

Help me please and thanks

Mathematics

1 answer:

leva [86]3 years ago

3 0

Answer:

A. (1, -4)

Step-by-step explanation:

You can try the answers to see which works. (The first one does.)

Or, you can solve the equations algebraically. Equating y-values works well here:

2x -6 = -2x -2

4x = 4 . . . . . . . add 2x+6 to both sides; next divide by 4

x = 1 . . . . . . . . shows you selection A is correct

___

A graphing calculator can show you the point of intersection. Perhaps this is the way to go, since the unit seems to be on graphing systems of equations. Both of these equations are in slope-intercept form (y=mx+b), so are easily graphed by starting from the y-intercept (b) and using the slope (m=rise/run) to find another point on the line.

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The radius of the large sphere is double the radius of the small sphere. How many times does the volume of the large sphere than

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Answer:

8 times larger.

Step-by-step explanation:

The radius of the large sphere is double the radius of the small sphere.

Question asked:

How many times does the volume of the large sphere than the small sphere

Solution:

Let radius of the small sphere =  $x$ 

As the radius of the large sphere is double the radius of the small sphere:

Then, radius of the large sphere = $2x$

To find that how many times is the volume of the large sphere than the small sphere, we will divide the volume of large sphere by volume of small sphere:-

For smaller sphere: $Radius = x$

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$=\frac{4}{3} \pi (2x)^{3}$

Now, we will divide volume of the larger by the smaller one:

$=\frac{4}{3} \pi (2x)^{3}\div\frac{4}{3} \times\frac{\pi }{1 } \times x^{3}\\ \\ =\frac{4}{3} \pi\times8x^{3} \times\frac{3}{4\pi }\ \times\frac{1}{x^{3} }$

$\frac{4}{3}\pi\ is \ canceled\ by\ \frac{3}{4\pi } \ and\ also\ x^{3} is\ canceled\ by \ \frac{1}{x^{3} }$

Now, we have

= $\frac{8}{1}$

Therefore, the volume of the large sphere is 8 times larger than the smaller sphere.

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dolphi86 [110]

Answer:

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Step-by-step explanation:

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