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Tom [10]
3 years ago
9

Which expression is equal to 5/(sqrt)11?

Mathematics
2 answers:
horrorfan [7]3 years ago
8 0

Answer:

Option A is correct

the expression is equal to \frac{5}{ \sqrt{11}} is \frac{5\sqrt{11}} {11}

Explanation:

Given expression is, \frac{5}{ \sqrt{11}}

Multiply and divide by the denominator by \sqrt{11} in the given expression, we have,

\frac{5}{\sqrt{11}} \times \frac{\sqrt{11}} { \sqrt{11}}

or

\frac{5 \cdot \sqrt{11}} {\sqrt{11} \cdot \sqrt{11}}

use : \sqrt{a}\cdot\sqrt{a}=(\sqrt{a} )^2 = a

then;

\frac{5\sqrt{11}} { (\sqrt{11})^2} =\frac{5\sqrt{11}} {11}

Therefore, the expression is equal to \frac{5}{ \sqrt{11}} is, \frac{5\sqrt{11}} {11}


Nadya [2.5K]3 years ago
6 0
5/√11
In this case:
if you want to delete the roots in the denominator you have to multiply the numerator and the denominator by √11; therefore:
(5/√11)(√11/√11)=5√11/11.

answer; a)5√11/11
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Which sequences of transformations confirm the congruence of shape II and shape I?
mylen [45]

Answer:

1. When we reflect the shape I along X axis it will take the shape I in first quadrant, and then if we rotate the shape I by 90° clockwise, it will take the shape again in second quadrant . So we are not getting shape II. This Option is Incorrect.

2. Second Option is correct , because by reflecting the shape I across  X axis and then by 90° counterclockwise rotation will take the Shape I in second quadrant ,where we are getting shape II.

3. a reflection of shape I across the y-axis followed by a 90° counterclockwise rotation about the origin takes the shape I in fourth Quadrant. →→ Incorrect option.

4. This option is correct, because after reflecting the shape through Y axis ,and then rotating the shape through an angle of 90° in clockwise direction takes it in second quadrant.

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Pls help this question bamboozles me and I am now sitting here confused
UkoKoshka [18]

Answer:

10+3pi

Step-by-step explanation:

The perimeter of of the shaded region is

AC+CT+marcSBT+SA

*Finding AC

The diagonals of a rectangle are equal is measurement. Since RB is a radius of the circle, then RB is 6. Since AC and RB are both diagonals of the rectangle, then AC is also 6.

*Finding CT

CT=RT-RC where RC is the width of the rectangle

Also RT is a radius so we have that

CT=6-RC

*Finding marcSBT

The circumference of a whole circle is 2pi*r.

We have a quarter of this with r=6.

1/4*2pi(6)

1/4*12pi

3pi

*Finding SA

SA=RS-AR

RS is a radius of the circle and AR is the length of the rectangle.

So we have that this can be rewritten as

SA=6-AR

Let's put these parts together:

6+6-RC+3pi+6-AR

Simplifying:

18-RC-AR+3pi

18-(RC+AR)+3pi

18-8+3pi (Remember length plus width equal 8)

10+3pi

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3 years ago
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Answer:

9+10=21

Step-by-step explanation:

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3 years ago
Mary is rolling a standard six-sided die and spinning on a spinner with the number 1-8.
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Answer:

a) Dice and spinner are different objects, with no relation between themselves, and thus her dice rolls and spinning outcomes are independent.

b) \frac{1}{48} probability of her rolling a 4 and spinning an 8.

c) \frac{1}{8} probability of her rolling an even number and spinning a number less than 3.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

A) Are her dice rolls and spinning outcomes independent or dependent?

Dice and spinner are different objects, with no relation between themselves, and thus her dice rolls and spinning outcomes are independent.

B) What is the probability of her rolling a 4 and spinning an 8?

Since the events are independent, we find each separate probability and multiply them.

Probability of rolling a 4:

One side out of 6 on the dice. So

P(A) = \frac{1}{6}

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One side out of 8 on the spinner. So

P(B) = \frac{1}{8}

Probability of rolling a 4 and spinning an 8:

P(A \cap B) = P(A)P(B) = \frac{1}{6} \times \frac{1}{8} = \frac{1}{48}

\frac{1}{48} probability of her rolling a 4 and spinning an 8.

C) What is the probability of her rolling an even number and spinning a number less than 3?

Since the events are independent, we find each separate probability and multiply them.

Probability of rolling an even number:

2, 4 or 6(3 sides out of 6). So

P(A) = \frac{3}{6} = \frac{1}{2}

Probability of spinning a number less than 3:

Two numbers(1 or 2) out of 8 on the spinner. So

P(B) = \frac{2}{8} = \frac{1}{4}

Probability of rolling an even number and spinning a number less than 3:

P(A \cap B) = P(A)P(B) = \frac{1}{2} \times \frac{1}{4} = \frac{1}{8}

\frac{1}{8} probability of her rolling an even number and spinning a number less than 3.

8 0
3 years ago
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