Help ASAP!!! I'll give brainlest to whoever explains it right

The rabbit population in a certain area is 200% of last year's population. There are 900 rabbits this year. How many were ther

Nezavi [6.7K]

There would be 450 rabbits last year.

Since 900 is double 450, 200% of 450 is 900. (450 would be 100%, so you would double it).

3 0

3 years ago

Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y

ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; $(x^2-4)^2y'' + (x + 2)y' + 7y = 0$

The above equation can be better expressed as:

$y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0$

The pattern of the normalized differential equation can be represented as:

y'' + p(x)y' + q(x) y = 0

This implies that:

$p(x) = \dfrac{(x+2)}{(x^2-4)^2} \$

$p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \$

$p(x) = \dfrac{1}{(x+2)(x-2)^2}$

Also;

$q(x) = \dfrac{7}{(x^2-4)^2}$

$q(x) = \dfrac{7}{(x+2)^2(x-2)^2}$

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

$\lim \limits_{x \to-2} (x+ 2) p(x) = \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}$

$\implies \lim \limits_{x \to2} \dfrac{1}{(x-2)^2}$

$\implies \dfrac{1}{16}$

$\lim \limits_{x \to-2} (x+ 2)^2 q(x) = \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}$

$\implies \lim \limits_{x \to2} \dfrac{7}{(x-2)^2}$

$\implies \dfrac{7}{16}$

Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

5 0

3 years ago

A town's population has been growing linearly. In 2003, the population was 59.000 and the population has been growing by 1,700 p

Rudiy27

Answer:

In 2003, the population was 59000 and the population has been growing by 1,700 people each year.

A.

The equation will be:

59000+1700x = (population 'x' years after 2003)

For x, you plug in the amount of years after 2003.

Like if it is the year 2003, the population is $59000+1700(0)$

= 59000

when it is year 2005, the population is $59000+1700(2)$

= 62400

B.

The town's population in 2007 will be :

$(2007-2003=4)$

$59000+1700(4)$

Population = 65800

C.

$59000+1700x=77700$

=> $1700x=18700$

x = 11

Means $2003+11=2014$

Hence, by year 2014 the population will be 77700.

5 0

3 years ago

Which expressions show the expanded form for 200.06? Choose all answers that are correct. A. 2 × 100 + 0 × 1 + 0 × 1/10 + 6 × 1/

saveliy_v [14]

Answer:

Therefore,

Correct options are

A) 2 × 100 + 0 × 1 + 0 × 1/10 + 6 × 1/100

D) 2 × 100 + 6 × 1/100

Step-by-step explanation:

Given:

Number is

200.06

For option A)

2 × 100 + 0 × 1 + 0 × 1/10 + 6 × 1/100

= 200 + 0 + 0 + 0.06

= 200.06

Which is CORRECT.

For option B)

2 × 100 + 0 × 1 + 0 × 1/100 + 6 × 1/1,000

= 200 + 0 + 0 + 0.006

=200.006

Which is INCORRECT.

For option C)

2 × 100 + 6 × 1/10

= 200 + 0.6

= 200.6

Which is INCORRECT.

For option D)

2 × 100 + 6 × 1/100

= 200 + 0.06

= 200.06

Which is CORRECT.

Therefore,

Correct options are

A) 2 × 100 + 0 × 1 + 0 × 1/10 + 6 × 1/100

D) 2 × 100 + 6 × 1/100

5 0

2 years ago

Help pls I really need it pls

Marianna [84]

The value of x is 7 because 8/24 = 1/3 so find 1/3 of 21

4 0

2 years ago