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2 years ago

HELP ME PLEASEEEEE

Mathematics

1 answer:

Ne4ueva [31]2 years ago

4 0

Answer:

x = 4

Step-by-step explanation:

x(x + 8) = 48

x² + 8x = 48

x² + 8x - 48 = 0

times into -48

add into 8

(x - 4)(x + 12) = 0

x - 4 = 0

x = 4

x + 12 = 0

x = -12

A length cannot be a negative number therefore x = 4

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HI I NEED HELP ASAP I GIVE BRAINLEST IF YOU GET IT RIGHT

lord [1]

It’s c :) I did the test just trust me

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3 years ago

A spinner for a board game consists of a cardboard circle with two plastic arrows anchored to its center. The arrows are congrue

tekilochka [14]

Answer:

Option (c) is correct.

The approximate total area of the plastic triangles on the spinner is 2 × 3.9 square centimeters = 7.7 square centimeters

Step-by-step explanation:

Given:A spinner for a board game consists of a cardboard circle with two plastic arrows anchored to its center. The arrows are congruent isosceles triangles connected at their bases.

also, Given: The base of each triangle measures 2 centimeters and the perimeter of each triangle is 10 centimeters.

We have to find the approximate total area of the plastic triangles on the spinner.

Perimeter of triangle is the sum of sides.

Since given the triangle to be isosceles .

Let the two equal side be x cm, then,

Perimeter of given triangle = 1 0

⇒ x + x + 2 = 1 0

⇒ 2x = 8

⇒ x = 4

Thus, side of triangle is 4 cm.

Now we find the area of isosceles triangle.

We first find the height, using Pythagoras theorem,

$(AC)^2=(AD)^2+(DC)^2$

Putting values, we get,

$(4)^2=(AD)^2+(1)^2$

Solving we get,

$AD=3.87$

Thus, area of one isosceles triangle $A=\frac{1}{2} bh$

area of one isosceles triangle $A=\frac{1}{2} \times 2 \times 3.87$

On solving we get,

Approximate area of one plastic triangles on the spinner is 3.9 square centimeters.

Thus, the approximate total area of the plastic triangles on the spinner is 2 × 3.9 square centimeters = 7.7 square centimeters

Option (c) is correct.

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3 years ago

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3 years ago

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3 years ago

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A 5×6 rectangular grid with unit cells is given. Let A(0, 0) and B(5, 6) be the bottom-left corner and top-right corner, respect

harina [27]

Answer:

462 paths from A to B

Step-by-step explanation:

The question is incomplete. However, a possible question is to determine the number of possible paths on the grid map.

The first step is to represent the grid map itself. (See attachment 1)

From the question, we understand that:

Only right movement is allowed in the horizontal direction

Only up movement is allowed in the vertical direction

There are a several number of ways to navigate through. However, one possible way is in attachment 2

In attachment 2,

R represents the right movement
U represents the up movement

And we have:

$R = 5$ and $U = 6$

The number of possible paths (N) is then calculated as:

$N = \frac{(N + U)!}{N!U!}$

Substitute values for N and U

$N = \frac{(5 + 6)!}{5!6!}$

$N = \frac{11!}{5!6!}$

$N = \frac{39916800}{120 * 720}$

$N = \frac{39916800}{86400}$

$N = 462$

<em>Hence, there are 462 possible paths from A to B</em>

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3 years ago