Answer:
1. Step 2: 2a-6+6 Step 3: 2a
2. Step 2: 8(2d+3)
Step by step explanation:
Here’s my work form what I seen:
You'll have to c<span>ompass tip on A and draw a small ark with pencil approximately in the middle above AB line, now compass tip to point B and cross the ark you made previously.
Do the same on the opposite side without making any change to the compass
Join the lines where crosses of arks on the both side meet and then ,it's done.</span>
Answer:
57.72 in^2
Step-by-step explanation:
Question 1. Shapes are triangle, semi-circle, and rectangle.
Question 2.Find area of rectangle first. Then area of triangle and circle. Subtract area of triangle and circle. Then add the difference with the rectangles area.
Question 3.
Rectangle's area:<u>48 in^2</u>
Triangles area:8*4/2= <u>16 in^2</u>
Circle Area: pi*r^2/2(since its a semi-circle)
3.14*2^2=3.14*4=12.56/2=<u>6.28 in^2</u>
Question 4.
16-6.28=9.72
9.72+48=57.72 in^2
Answer:
About 609,000 Cowboy stadiums could fit inside of Mount Everest
Step-by-step explanation:
we have
The estimate volume of Mount Everest is at around 
The Dallas Cowboys Stadium has a volume of 
step 1
Convert ft³ to km³
we know that
1 km=3,280.84 ft
so

step 2
To find how many Cowboy stadiums could fit inside of Mount Everest, divide the volume of Mount Everest by the volume of the Dallas Cowboys Stadium

Round to the nearest Thousands

The volume of Mount Everest is about 609,000 times greater than the volume of the Dallas Cowboys Stadium
The length of material needed for the border is the perimeter of the backyard play area
<h3>How to calculate the
length of
material needed </h3>
The area of the play area is given as:

The area of a trapezoid is calculated using:

Where L1 and L2, are the parallel sides of the trapezoid and H represents the height.
The given parameter is not enough to solve the length of material needed.
So, we make use of the following assumed values.
Assume that the parallel sides are: 25 feet and 31 feet long, respectively.
While the other sides are 10.2 feet and 8.2 feet
The length of material needed would be the sum of the above lengths.
So, we have:


Using the assumed values, the length of material needed for the border is 74.4 feet
Read more about perimeters at:
brainly.com/question/17297081