Question

The sum of three consecutive even integers is 126. Find the integers.

Answer 1

Answer:

40, 42 and 44

Step-by-step explanation:

An Integer is even, if it's divisible by two. it's also a multiple of two.

let first integer= Y note : Y is an even number.

second integer= (Y+2)

third integer = (Y+4)

from the question,

Y+Y+2+Y+4= 126

3Y+6 = 126

3Y = 126-6

3Y = 120

dividingbothsides by (3)

3Y/3 = 120/3

Y= 40

therefore, the even integers are:

40

(Y+2)= 40+2= 42

(Y+4) =40+4= 44

check!!!

adding the three numbers

40+42+44= 126

Answer 2

Step-by-step explanation:

x+ x+1+ x+2=126

3x+3=126

3x=126-3

3x=123

divide each side by 3

x=41

x+1=42

x+2=43

check your answer by adding the three integers:

41+42+43=126