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dmitriy555 [2]
2 years ago
8

The sum of three consecutive even integers is 126. Find the integers.

Mathematics
2 answers:
VikaD [51]2 years ago
7 0

Answer:

<h3>40, 42 and 44</h3>

Step-by-step explanation:

<h3>An Integer is even, if it's divisible by two. it's also a multiple of two.</h3>

let first integer= Y note : Y is an even number.

second integer= (Y+2)

third integer = (Y+4)

from the question,

Y+Y+2+Y+4= 126

3Y+6 = 126

3Y = 126-6

3Y = 120

dividingbothsides by (3)

3Y/3 = 120/3

Y= 40

therefore, the even integers are:

40

(Y+2)= 40+2= 42

(Y+4) =40+4= 44

<h2>check!!!</h2><h2>adding the three numbers</h2>

<h2>40+42+44= 126</h2>
harkovskaia [24]2 years ago
3 0

Step-by-step explanation:

x+ x+1+ x+2=126

3x+3=126

3x=126-3

3x=123

divide each side by 3

x=41

x+1=42

x+2=43

check your answer by adding the three integers:

41+42+43=126

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