The sum of three consecutive even integers is 126. Find the integers.
2 answers:
Answer:
<h3>40, 42 and 44</h3>
Step-by-step explanation:
<h3>An Integer is even, if it's divisible by two. it's also a multiple of two.</h3>
let first integer= Y note : Y is an even number.
second integer= (Y+2)
third integer = (Y+4)
from the question,
Y+Y+2+Y+4= 126
3Y+6 = 126
3Y = 126-6
3Y = 120
dividingbothsides by (3)
3Y/3 = 120/3
Y= 40
therefore, the even integers are:
40
(Y+2)= 40+2= 42
(Y+4) =40+4= 44
<h2>check!!!</h2><h2>adding the three numbers</h2>
<h2>40+42+44= 126</h2>
Step-by-step explanation:
x+ x+1+ x+2=126
3x+3=126
3x=126-3
3x=123
divide each side by 3
x=41
x+1=42
x+2=43
check your answer by adding the three integers:
41+42+43=126
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