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grandymaker [24]
3 years ago
15

What is x-x+3+x? I don't really get this ^^

Mathematics
2 answers:
fenix001 [56]3 years ago
4 0

Answer: 3+x

Step-by-step explanation: Variables cannot mix with non-variables so x-x = 0x. 0x + x = x. x +3 = 3+x or x+3. Brainliest please?

kipiarov [429]3 years ago
3 0

Answer:

4x is the answer

Step-by-step explanation:

3x + x= 4x + x = 5x - x = 4x

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If a*b*c=1197, find the value of c when a=21 and b=3 Note that * = Multiplication. a. 19 b. 13 c. 9 d. 2 e. Other
Hunter-Best [27]

Answer:

c = 19

Step-by-step explanation:

a*b*c=1197

Let a =21 and b= 3

21*3*c = 1197

63c = 1197

Divide each side by 63

63c/63 = 1197/63

c =19

7 0
4 years ago
How many 1/3 inch cubes does it take to fill a box with width 2 2/3 inches, lengths 3 1/3 inches, and height 2 1/3 inches?
Nataly [62]

Answer:

560 cubes

Step-by-step explanation:

width: 8 cubes

length: 10 cubes

height: 7 cubes

volume: 8*10*7=560

divided l, w, and h by 1/3 to get them in cubes

7 0
3 years ago
Read 2 more answers
Help me please. i've tried this so many times, writing it out, calculator. nothing's worked
likoan [24]

Answer:

-27

Step-by-step explanation:

y7 + 4x

(-1)7 + 4(-5)

-7 + (-20)

-27

8 0
3 years ago
?!?!?!?!?!!??!!!!?!!?need help
sladkih [1.3K]

Step-by-step explanation:

answer is 40.56

approx 40.60

8 0
3 years ago
If 8 identical blackboards are to be divided among 4 schools,how many divisions are possible? How many, if each school mustrecei
MAXImum [283]

Answer:

There are 165 ways to distribute the blackboards between the schools. If at least 1 blackboard goes to each school, then we only have 35 ways.

Step-by-step explanation:

Essentially, this is a problem of balls and sticks. The 8 identical blackboards can be represented as 8 balls, and you assign them to each school by using 3 sticks. Basically each school receives an amount of blackboards equivalent to the amount of balls between 2 sticks: The first school gets all the balls before the first stick, the second school gets all the balls between stick 1 and stick 2, the third school gets the balls between sticks 2 and 3 and the last school gets all remaining balls.

 The problem reduces to take 11 consecutive spots which we will use to localize the balls and the sticks and select 3 places to put the sticks. The amount of ways to do this is {11 \choose 3} = 165 . As a result, we have 165 ways to distribute the blackboards.

If each school needs at least 1 blackboard you can give 1 blackbooard to each of them first and distribute the remaining 4 the same way we did before. This time there will be 4 balls and 3 sticks, so we have to put 3 sticks in 7 spaces (if a school takes what it is between 2 sticks that doesnt have balls between, then that school only gets the first blackboard we assigned to it previously). The amount of ways to localize the sticks is {7 \choose 3} = 35. Thus, there are only 35 ways to distribute the blackboards in this case.

4 0
3 years ago
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