Answer: The correct option is (B) less than 2.
Step-by-step explanation: Given that Y varies directly with X and has a constant rate of change of 6.
We are to find the possible value of X when the value of Y is 11.
Since Y varies directly with X, so we can write
![Y\propto X\\\\\Rightarrow Y=kx~~~~~~~~~~~~~~~(i),~~~~~~~~~\textup{[where 'k' is the constant of variation]}](https://tex.z-dn.net/?f=Y%5Cpropto%20X%5C%5C%5C%5C%5CRightarrow%20Y%3Dkx~~~~~~~~~~~~~~~%28i%29%2C~~~~~~~~~%5Ctextup%7B%5Bwhere%20%27k%27%20is%20the%20constant%20of%20variation%5D%7D)
Since the rate of change is constant and is equal to 6, so we must have
So, from equation (i), we have
Now, when Y = 11, then from equation (ii), we get
Thus, the value of X is less than 2 when Y = 11.
Option (B) is CORRECT.
Answer:
First: 2x-3y+-48
Second:2x+y+0
Step-by-step explanation:
I think their correct but hopefully they helped!
Answer: 27
Step-by-step explanation:
Answer:
the answer is irrational (goes on forever) ... look at image...
I assume that the answer that you were to provide is
3 R 9 (3 remainder 9 )
or
Step-by-step explanation:
X-0.9 = 4.5
+0.9 +0.9
x = 5.4
( to get rid of the -0.9 beside the x, u have to do the opposite operation on both sides. if its -0.9, u have to add 0.9 on both sides)
not sure about the first one.
