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Y_Kistochka [10]
3 years ago
13

Simplify the following expression.

Mathematics
1 answer:
AveGali [126]3 years ago
3 0
1/6 is equal to 2/12. 3/4 is the simplified answer.
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Rewrite the function f(x)=2(x-2)^2-5 and in the form ax^2+bx+c
Ira Lisetskai [31]

Answer:

Step-by-step explanation:

f(x)=2(x-2)²-5

f(x)=2(x²-4x+4)-5

f(x)=2x²-8x+3

7 0
3 years ago
The sum of fifteen and six times a number t is eighty one what is the number
yKpoI14uk [10]

Answer: t=11 :))


Step-by-step explanation:

15+6t=81

6t=81-15

6t=66

6t/6=66/6

t=11

7 0
2 years ago
The box on the left is 8 inches wide and 8 inches tall what is the surface area of the box
TiliK225 [7]

Answer:

384 inches

Step-by-step explanation:

8 x 8 = 64

one face of the box is 64

6 faces of the box would be 384

6 0
3 years ago
Read 2 more answers
Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar.
Degger [83]

Answer:

So do you already have the answer? Also 1/20 looks right.

Step-by-step explanation:

8 0
3 years ago
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10. Two lighthouses are located on a north-south line.
Kamila [148]

The question is an illustration of bearing (i.e. angles) and distance (i.e. lengths)

The distance between both lighthouses is 5783.96 m

I've added an attachment that represents the scenario.

From the attachment, we have:

\mathbf{\angle A = 180^o - 120^o\ 43'}

Convert to degrees

\mathbf{\angle A = 180^o - (120^o +\frac{43}{60}^o)}

\mathbf{\angle A = 180^o - (120^o +0.717^o)}

\mathbf{\angle A = 180^o - (120.717^o)}

\mathbf{\angle A = 59.283^o}

\mathbf{\angle B = 39^o43'}

Convert to degrees

\mathbf{\angle B = 39^o + \frac{43}{60}^o}

\mathbf{\angle B = 39^o + 0.717^o}

\mathbf{\angle B = 39.717^o}

So, the measure of angle S is:

\mathbf{\angle S = 180 - \angle A - \angle B} ---- Sum of angles in a triangle

\mathbf{\angle S = 180 - 59.283 - 39.717}

\mathbf{\angle S = 81}

The required distance is distance AB

This is calculated using the following sine formula:

\mathbf{\frac{AB}{\sin(S)} = \frac{AS}{\sin(B)} }

Where:

\mathbf{AS = 3742}

So, we have:

\mathbf{\frac{AB}{\sin(81)} = \frac{3742}{\sin(39.717)}}

Make AB the subject

\mathbf{AB= \frac{3742}{\sin(39.717)} \times \sin(81)}

\mathbf{AB= 5783.96}

Hence, the distance between both lighthouses is 5783.96 m

Read more about bearing and distance at:

brainly.com/question/19017345

5 0
2 years ago
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