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Leni [432]
2 years ago
6

PLEASEE HELP!!!!!!!!!!! QUESTION IS IN THE IMAGE

Mathematics
1 answer:
Lena [83]2 years ago
4 0
3 because math and number
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Simplify the expression.<br> 3[(15-332-4]
lesya692 [45]

Answer:

-963

Step-by-step explanation:

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3 years ago
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Given f(x)=4x+5 and g(x)= x^2+x; find (f∘g)(-5)<br> Please show all steps thank you
Greeley [361]

Answer:

(f\circ g)(-5)=85

Step-by-step explanation:

We are given:

\displaystyle f(x)=4x+5\text{ and } g(x)=x^2+x

And we want to find:

(f\circ g)(-5)

This is equivalent to:

\displaystyle =f(g(-5))

So, we will evaluate g(-5) first, which yields:

\displaystyle g(-5)=(-5)^2+(-5)=25-5=20

So:

=f(g(-5))=f(20)

Then:

\displaystyle f(20)=4(20)+5=80+5=85

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(f\circ g)(-5)=85

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3 years ago
In the cafeteria tables are arranged in groups of 4, with each table seating 8 students. How many students can sit at 10 groups
Arisa [49]
4 tables = 1 group. So in 10 groups of tables, there are 40 tables. Each table seats 8 students, so you multiply 8 by 40, and that leaves your answer as 320 students. :)
4 0
2 years ago
How do I solve this? can someone please help? thank you! y=3x+4 y=x-2 ​
Alecsey [184]

Answer:

Step-by-step explanation:

y = 3x+4 and y = x-2

3x+4 = x-2

2x+4 = -2

2x = -6

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8 0
3 years ago
Which expression is equivalent to 6x^2 + 13x + 5?
hodyreva [135]

The signs of the x-term and the constant term are both positive, so the signs of the constants in the binomial factors must be the same and must both be positive. The only offering that meets that requirement is

... C (2x+1)(3x+5)

_____

If you multiply that out, you get 6x² + 10x + 3x + 5 = 6x² +13x +5, as required.

The sign of the constant term is the product of the signs of the constants in the binomial factors: (+1)·(+5). We want a positive sign for the constant, so both binomial factor constants must have the same sign.

When the signs of the binomial factor constants are the same, the x-term constant will match them. Thus, for a positive x-term constant, both binomial factor constants must be positive.

3 0
2 years ago
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