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Flura [38]
2 years ago
11

Clara is stacking cups; she put 45 plastic cups in the first stack, 38 plastic cups in the second stack, 31 plastic cups in the

third stack, and 24 plastic cups in the fourth stack. What kind of sequence is this?
Mathematics
1 answer:
Levart [38]2 years ago
7 0

Answer:

Subtracting 7

Step-by-step explanation:

<u><em>Given:</em></u>

<em>Clara is stacking cups; she put 45 plastic cups in the first stack, 38 plastic cups in the second stack, 31 plastic cups in the third stack, and 24 plastic cups in the fourth stack. </em>

<u><em>To Find:</em></u>

<em>What kind of sequence is this?</em>

<u><em>Solve:</em></u>

<em>Let's make a table:</em>

<em />

<em>[1 stack]  45 </em>

<em>[2 stack] 38</em>

<em>[3 stack] 31</em>

<em>[4 stack] 24</em>

<em />

<em>Now all we have to do is subtract to see what each is:</em>

<em>45 - 38 = 7</em>

<em>38 - 31 = 7</em>

<em>31 - 24 = 7</em>

<em>Thus,</em>

<em>[1 stack]  45 ⇒ 7</em>

<em>[2 stack] 38 ⇒ 7 </em>

<em>[3 stack] 31 ⇒ 7 </em>

<em>[4 stack] 24 ⇒ 7 </em>

<em>Hence, each stack is going down by 7.</em>

<em />

<u><em>Kavinsky</em></u>

<em />

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kow [346]

Answer:

h=40t+9700

where the elevation, h, is in feet and time, t, is in minutes.

Step-by-step explanation:

At the time, t_1=15 min, the elevation, h_1= 10,300 feet and

at the time t_2= 30 min, the elevation, h_2=10,900 feet.

As they are hiking a steady incline, so the change in the elevation with respect to time will be constant.

So, there will be a linear relationship between the elevation and the time.

Let h be the elevation at any time instant t, so the linear relation among these quantities is

h=mt+C_0\;\cdots(i)

where m is the rate of change of elevation with respect to time and C_0 is constant.

The change in the elevation, \Delta h=h_2-h_1= 10,900-10,300=600 feet.

and the change in time, \Delta t=t_2-1_1=30-15=15 min.

So, change in the elevation in unit time,

m=\frac{\Delat h}{\Delta t}=\frac{600}{15}=40 feet/min.

Now, from equation (i)

h=40t+C_0

As the elevation, h=h_1 at time t=t_1, so

10,300=40\times15+C_0

\Rightarrow C_0=9700

Hence, the required equation is

h=40t+9700

where the elevation, h, is in feet and time, t, is in minutes.

3 0
3 years ago
It takes 32 hours for a motorboat moving downriver to get from pier A to pier B. The return journey takes 48 hours. How long doe
lina2011 [118]

Answer:

Time taken by the un powered raft to cover this distance is T = 192.12 hr

Step-by-step explanation:

Let speed of boat = u \frac{km}{hr}

Speed of current = v \frac{km}{hr}

Let distance between A & B = 100 km

Time taken in downstream = 32 hours

32 = \frac{100}{u +v}

u + v = \frac{100}{32}

u + v = 3.125 ------ (1)

Time taken in upstream = 48 hours

48 = \frac{100}{u -v}

u -v = \frac{100}{48}

u - v = 2.084 ------- (2)

By solving equation (1) & (2)

u = 2.6045 \frac{km}{hr}

v = 0.5205 \frac{km}{hr}

Now the time taken by the un powered raft to cover this distance

T = \frac{100}{v}

Because un powered raft travel with the speed of the current.

T = \frac{100}{0.5205}

T = 192.12 hr

Therefore the  time taken by the un powered raft to cover this distance is

T = 192.12 hr

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Norma-Jean [14]

Answer:

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Step-by-step explanation:

1674/3 = 558 (An even number, yay)

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556 + 558 + 560

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