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3 years ago

The length of a rectangle is 5 inches and the width is x inches. What is the perimeter, in inches?

Mathematics

1 answer:

VMariaS [17]3 years ago

5 0

<h3>Answer: 2x+10 inches</h3>

Explanation:

There are 2 opposite sides that are x inches long, so they add to x+x = 2x

Then there are 2 opposite sides that are 5 inches long, which add to 5+5 = 10

Overall, the four sides add to 2x+10 inches

You could also apply the formula below

P = 2L+2W

P = 2x+2*5

P = 2x+10

That formula is the same as P = 2(L+W)

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60 pts for the person that answer and brainiest

vodomira [7]

Answer:

the answer is b because it justifies why the theory of evolution is a theory not a law.

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3 years ago

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PLZ Hurry!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!The sum of two numbers is 19 and their difference is 7, What are the two num

yuradex [85]

Answer:

13 and 6

Step-by-step explanation:

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2 years ago

How do you find the absolute extrema of this function?<br> f(x) = x+3x^(2/3); Interval is [-10,1]

Step2247 [10]

$\bf f(x)=x+3x^{\frac{2}{3}}\implies \cfrac{dy}{dx}=1+3\left(\frac{2}{3}x^{-\frac{1}{3}} \right)\implies \cfrac{dy}{dx}=1+\cfrac{2}{\sqrt[3]{x}}
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\cfrac{dy}{dx}=\cfrac{\sqrt[3]{x}+2}{\sqrt[3]{x}}\implies 0=\cfrac{\sqrt[3]{x}+2}{\sqrt[3]{x}}\implies 0=\sqrt[3]{x}+2\implies -2=\sqrt[3]{x}
\\\\\\
(-2)^3=x\implies \boxed{-8=x}\\\\
-------------------------------\\\\
0=\sqrt[3]{x}\implies \boxed{0=x}$

now, f(0) = 0, and f(-8) is an imaginary value or no real value.

now, f(-10) will also give us an imaginary value

and f(1) = 4

so, doing a first-derivative test on 0, is imaginary to the left and positive on the right, and before and after 1, is positive as well, so f(x) is going up on those intervals.

however, f(0) is 0 and f(1) is higher up, so the absolute maximum will have to be f(1), and we can use f(0) as a minimum, and since it's the only one, the absolute minimum.

the other two, the endpoint of -10 and the critical point of -8, do not yield any values for f(x).

8 0

3 years ago

What is the solution of sqrt 1-3x =x+3

Sonbull [250]

Answer:

x= -1

Step-by-step explanation:

1-3x=x²+6x+9

1-3x-x²-6x-9=0

-8-9x-x²=0

x²+9x+8=0

x²+8x+x+8=0

(x+8)(x+1)=0

x+8=0

x+1=0

sqrt 1-3(-8)=-8+3

sqrt 1-3(-1)=-1+3

5=-5

2=2

x≠8

x=-1

8 0

3 years ago

Look at the figure. Which construction is illustrated? 7. Which is the equation of the line with slope 3 that contains point (−1

kenny6666 [7]

Answer:

Option B

Step-by-step explanation:

I can't do the 'figure question' because it lacks info, but I can answer the point-slope question.

Point-slope form is: $y-y_1=m(x-x_1)$

'm' - slope

'(x1, y1)' - point

We are given the slope of 3 and the point (-1, 5).

Replace 'x1', 'y1', and 'm' with the appropriate values.

$y-y_1=m(x-x_1)\rightarrow \boxed{y-5=3(x+1)}$

Option B should be the correct answer.

7 0

3 years ago