A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by gi

Question

2 years ago

10

ven equation. Using this equation, find the time that rocket will hit the ground, to the nearest 100th of second. Y=-16x^2+157x+104

1 answer:

GuDViN [60] · Answer 1 · 2023-01-19T02:15:05+03:00

The time that rocket will hit the ground, to the nearest 100th of second is 10.43 seconds

Given the equation representing the height reached by a rocket as:

$y = -16x^2 + 157x + 104$

The rocket will hit the ground when y = 0. Substituting y = 0 into the expression to get x;

$0 = -16x^2 + 157x + 104\\16x^2 - 157x - 104 = 0\\$

On factorizing:

x = 10.43 seconds

Hence the time that rocket will hit the ground, to the nearest 100th of second is 10.43 seconds