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3 years ago

Reducing the original price of an item is often called

2 answers:

7 0

Should be markdown, but if you have other options let me know and I'll tell you which it is. But if markdown is one of your choices, or if this is fill-in, it's markdown.

JulijaS [17]3 years ago

7 0

Answer:

<h2>Price reduction.</h2>

Step-by-step explanation:

The act of reducing the selling price of products in order to attract costumers is called Price Reduction. This comprehends a marketing strategy.

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Alexander needs to collect at least 120 cans for a food drive to urban community service credit he has already collected 64 item

Ahat [919]

Answer:

120-64=56

Step-by-step explanation:

3 0

3 years ago

Hello, can someone help me!! I have tried every combination possible and I still cannot find the answer. The picture shows the q

il63 [147K]

Answer:

5.01

Step-by-step explanation:

if she can go 6.7 miles in an hour, then the way we find out how much she does in 3/4 of an hour is divide 6.7 by 4. 6.7/4=1.67 and then, to get 3/4, we multiply 1.67 by 3.

Brainliest please

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3 years ago

3/5 of the students in a classroom are girls if there are 10 boys in the class how many total students are there

nata0808 [166]

16 students is the correct answer...
for every 5 boys there are 3 girls, so 20 boys 6 girls = the total of 16 students

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3 years ago

52.311 is greater than 52.31

Pavlova-9 [17]

52.311 is greater than 52.31 because look at 52.311 and 52.31

4 0

4 years ago

Suppose a parabola has an axis of symmetry at x=-5, a maximum height of 9, and passes through the point (-7,1). Write the equati

Nutka1998 [239]

the parabola has maximum at 9, meaning is a vertical parabola and it opens downwards.

it has a symmetry at x = -5, namely its vertex's x-coordinate is -5.

check the picture below.

so then, we can pretty much tell its vertex is at (-5 , 9), and we also know it passes through (-7, 1)

$\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} y=a(x- h)^2+ k\qquad \leftarrow \textit{using this one}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{}{ h},\stackrel{}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=-5\\ k=9 \end{cases}\implies y=a[x-(-5)]^2+9\implies y=a(x+5)^2+9$

$\bf \textit{we also know that } \begin{cases} x=-7\\ y=1 \end{cases}\implies 1=a(-7+5)^2+9 \\\\\\ -8=a(-2)^2\implies -8=4a\implies \cfrac{-8}{4}=a\implies -2=a \\\\[-0.35em] ~\dotfill\\\\ ~\hfill y=-2(x+5)^2+9~\hfill$

7 0

3 years ago