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2 years ago

Help helllllllllp asappp

Mathematics

1 answer:

valentinak56 [21]2 years ago

8 0

The numbers to complete the chart presented are 6, 5, 3, and the total pounds ordered were 15 pounds.

<h3>How to complete the chart?</h3>

Multiply the two numbers given:

3/4 x 8 = 6
1 1/4 x 4 = 5
1 1/2 x 2 = 3

<h3>What is the total of pounds ordered?</h3>

Now add the previous results to find out the total cheese.

1 + 6 + 5 + 3 = 15 pounds

Learn more about pounds in: brainly.com/question/17275505
#SPJ1

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Vince helped the pep club make sandwiches to raise money. He put two in each of 30 bags and 5 sandwiches in 26 family bags, and

tamaranim1 [39]

Answer is 181 sandwiches
Working steps
Firstly you want to work backwards and turn in equation
30*2+26*4+17=X
So 60+104+17=X
That means 181=X

Enjoy

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3 years ago

A student finds the product. Is his answer reasonable? 5,692 x 3 = 17,076 Estimate to check

lora16 [44]

Answer:

His answer is reasonable.

5,700 x 3 is around 17100

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3 years ago

Read 2 more answers

Here is 19 and 20 thank yall

Veseljchak [2.6K]

Answer:

19: The difference between the temperature in Fair Banks and Barlow is 3°F

20: -13°F, -10°F, 15°F, 24°F.

Step-by-step explanation:

I'm assuming that by "compare", it means to find the difference between temperatures in question 19. If it means something else, let me know and I'll try and help you find it.

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3 years ago

Read 2 more answers

Z is less than 2 and equal to or less than 8 intersection

insens350 [35]

Less than 2 = z < 2

Less than or equal to 8 = z ≤ 8

z ≤ 8

z < 2

8 0

3 years ago

Listed below are the measured radiation absorption rates? (in w/kg) corresponding to 11 cell phones. Use the given data to const

deff fn [24]

Answer:

The minimum value is 0.51

$Q_1= \frac{0.89+1.04}{2}= 0.965$

Median=Q2= 1.18

$Q_3= \frac{1.41+1.42}{2}= 1.415$

Max = 1.49

Step-by-step explanation:

We assume the following dataset:

1.18,1.41, 1.49,1.04,1.04,0.74,0.89,1.42,1.45,0.51,1.38

We order the dataset on increasing way and we have:

0.51 0.74 0.89 1.04 1.04 1.18 1.38 1.41 1.42 1.45 1.49

The minimum value is 0.51

The first quartile Q1 can be calculated with the first 6 observations: 0.51 0.74 0.89 1.04 1.04 1.18. The Q1 would be the average between the 3rd and 4th position:

$Q_1= \frac{0.89+1.04}{2}= 0.965$

For the median since the number of data represent an odd number than the median would be the position in the middle (6th)

Median=Q2= 1.18

The first quartile Q1 can be calculated with the last 6 observations: 1.18 1.38 1.41 1.42 1.45 1.49. The Q1 would be the average between the 3rd and 4th position:

$Q_3= \frac{1.41+1.42}{2}= 1.415$

And the maximum value for this case would be:

Max = 1.49

We can see the boxplot obtained on the figure attached.

5 0

3 years ago