Answer:
The answers to the questions are;
(a) P(At least 1 defective)
= 0.9883.
(b) P(At least 1 defective)
= 0.6409.
Step-by-step explanation:
There are 110 cards and 20 defectives.
a) The probability of at least one defective is given by
P(At least 1 defective) = 1 - P(0 defective)
P(0 defective) = 20C0 × (90C0)/(110C20) = 0.0116
1 - 0.0116 = 0.9883
b) For a set of 110 boards that has 5 defective and 105 non-defective
P(At least 1 defective) = 1 - P(0 defective)
P(0 defective) = (20C0)(90C5)/(110C5) = 0.35909
1-0.35909
= 0.6409
Answer:
2
Step-by-step explanation:
The distances have the ratio:
(C -A) = (2/3)(B -A)
C = (2/3)B +(1/3)A . . . . . add A
C = (2B +A)/3 . . . . . . . . combine terms
C = (2(4) +(-2))/3 = 6/3 = 2
The coordinate of C is 2.
48 it is counting up by odd numbers (3,5,7,9,11, 13
The answer is 0.1 or 1/10
Well, since a is Susan’s current age, we would add three to a to get her age in three years
So our expression would be:
a + 3